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borishaifa [10]
3 years ago
9

On a coordinate plane, 2 rectangles are shown. Rectangle P Q R S has points (negative 3, negative 5), (negative 2, negative 5),

(negative 2, negative 1), (negative 3, negative 1). Rectangle P double-prime Q double-prime R double-prime S double-prime has points (negative 5, 5), (negative 5, 4), (negative 1, 4), (negative 1, 5).Which rule describes the composition of transformations that maps rectangle PQRS to P''Q''R''S''?R0,270° ∘ T0,2(x, y)R0,180° ∘ T2,0 (x, y)T0,2 ∘ R0,270°(x, y)R0,2 ∘ T0,180°(x, y)
Mathematics
2 answers:
never [62]3 years ago
8 0
KaixyejziulooojuellwllnzjjikXkklw
Vinvika [58]3 years ago
7 0

Answer:

T0,2 ∘ R0,270°(x, y)

Step-by-step explanation:

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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
The question is below
Ad libitum [116K]

Answer:

£59.25

Step-by-step explanation:

Hello!

To solve this problem, we must:

  1. Solve for the length of the fence (aka height)
  2. Find the area of the lawn (trapezoid)
  3. Find the number of cans needed
  4. Find the price of all the cans

Area of a trapezoid, and why the formula works:

A trapezoid is a quadrilateral with one set of parallel sides known as bases. The other two sides are known as the legs.

To find the area of a trapezoid, we use the formula:

\frac{B_1 + B_2}{2}* h

This works because if we used the formula, we would be duplicating the trapezoid to form a rectangle with a side length of B1 + B2, and a height of h. Since the trapezoid is half of that, we divide by 2.

Solve for height:

The height is unknown but can be found using the Pythagorean Theorem.

The difference between the bases is the length of the bottom leg of the right triangle, and 17 is the hypotenuse.

Difference = 20 - 12 = 8

Hypotenuse = 17

  • 8² + fence² = 17²
  • 64 + fence² = 289
  • 225 = fence²
  • fence = 15

The height is 15

Solve for area:

Now we can solve for the area.

  • A = \frac{B_1 + B_2}{2} * h
  • A = \frac{12 + 20}{2} * 15
  • A = \frac{32}{2} * 15
  • A = 16 * 15 = 240

The area is 240

Cans:

The area of the lawn is 240 square meters. Each can cover 100 square meters.

  • 240 ÷ 100 = 2.4

Since we can't use part of a can, we round up to three whole cans.

The price of 3 cans :

  • 3 * 19.75
  • 59.25

£59.25

The Pythagorean Theorem:

The Pythagorean theorem is a very common geometry formula used to find the length of the hypotenuse in a right triangle, given the lengths of the two other bases.

The formula is : a^2 + b^2 = c^2

  • a is a leg
  • b is a leg
  • c is the hypotenuse

Images attached for your reference

7 0
2 years ago
Help please with this question
choli [55]

Answer:

They lose about 2.79% in purchasing power.

Step-by-step explanation:

Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.

Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about

... (1 +0.03/365)^365 ≈ 1.03045326

Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...

... 1.03045326 / 1.06 ≈ 0.9721 . . . items

That is, the loss of purchasing power is about ...

... 1 - 0.9721 = 2.79%

_____

If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.

7 0
3 years ago
Here's a story problem....
djverab [1.8K]
Where is the data? Show a picture if you could.
6 0
3 years ago
Read 2 more answers
Can someone please answer this math problem for me, please answer all of them if you can ​
ohaa [14]

Answer:

Q5

∠3 = ∠4

Q6.

∠S + ∠T = 90°

Q7.

∠X + ∠Y = 180°

Q8.

∠1 = ∠4

Q9.

∠K = ∠L

7 0
3 years ago
Read 2 more answers
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