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GarryVolchara [31]
2 years ago
5

The question is below

Mathematics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

£59.25

Step-by-step explanation:

Hello!

To solve this problem, we must:

  1. Solve for the length of the fence (aka height)
  2. Find the area of the lawn (trapezoid)
  3. Find the number of cans needed
  4. Find the price of all the cans

Area of a trapezoid, and why the formula works:

A trapezoid is a quadrilateral with one set of parallel sides known as bases. The other two sides are known as the legs.

To find the area of a trapezoid, we use the formula:

\frac{B_1 + B_2}{2}* h

This works because if we used the formula, we would be duplicating the trapezoid to form a rectangle with a side length of B1 + B2, and a height of h. Since the trapezoid is half of that, we divide by 2.

Solve for height:

The height is unknown but can be found using the Pythagorean Theorem.

The difference between the bases is the length of the bottom leg of the right triangle, and 17 is the hypotenuse.

Difference = 20 - 12 = 8

Hypotenuse = 17

  • 8² + fence² = 17²
  • 64 + fence² = 289
  • 225 = fence²
  • fence = 15

The height is 15

Solve for area:

Now we can solve for the area.

  • A = \frac{B_1 + B_2}{2} * h
  • A = \frac{12 + 20}{2} * 15
  • A = \frac{32}{2} * 15
  • A = 16 * 15 = 240

The area is 240

Cans:

The area of the lawn is 240 square meters. Each can cover 100 square meters.

  • 240 ÷ 100 = 2.4

Since we can't use part of a can, we round up to three whole cans.

The price of 3 cans :

  • 3 * 19.75
  • 59.25

£59.25

The Pythagorean Theorem:

The Pythagorean theorem is a very common geometry formula used to find the length of the hypotenuse in a right triangle, given the lengths of the two other bases.

The formula is : a^2 + b^2 = c^2

  • a is a leg
  • b is a leg
  • c is the hypotenuse

Images attached for your reference

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Step-by-step explanation:

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Carrie wished to build a rectangular dog run along theside of her garage. The garage will serve as one side of the fence. If she
Nat2105 [25]

Given:

Carrie has 180 ft of the fencing and wishes the fence to be 4times as long as it is wide.

To Find:

The area in square feet that the fencing encloses.

Answer:

The fence encloses 3600 sq ft.

Step-by-step explanation:

Let x denote the length of the dog run and y denote the width of the dog run.

Given that the garage wall serves as one side of the dog run, we are left with 3 other sides to instal the fence.

Carrie has 180ft of fencing with her, so the sum of the lengths of the 3 sides has to be equal to 180. We can represent this in the form of an equation as

x+y+y=180\\\\x+2y=180\\\\x=180-2y

We are also given that Carrie wishes the fence to be 4 times as long as it is wide.

So,

x=4y

Replacing this value into the first equation, we have

4y=180-2y\\\\
6y=180\\\\
y=30

Therefore,

x=(4)(30)=120

Thus, the length of the dog run is 120ft and the width is 30ft.

The area enclosed will be equal to the length multiplied with the width. So,

(120)(30)=3600

The fence encloses 3600 sq ft.


4 0
3 years ago
Find the length of the arc
pickupchik [31]

Answer:

23.6 or 1 4 × π × 8 = 2 π  if its not right let me know

Step-by-step explanation:

5 0
2 years ago
The figure shows a construction completed by hand.
Tresset [83]

Based on the construction, we can logically deduce that: A. yes; the compass was kept at the same width to create the arcs for points C and D.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

In Geometry, a line segment can be measured by using the following measuring instruments:

  • A scale (ruler)
  • A divider
  • A compass

<h3>What is an arc?</h3>

In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.

Based on the construction with arcs created above and below the line segment from points A, we can infer and logically deduce that it is true that the compass was kept at the same width to create the arcs for points C and D.

In conclusion, yes, the construction demonstrated how to bisect a line segment correctly by hand.

Read more on arcs here: brainly.com/question/11126174

#SPJ1

Complete Question:

The construction has a given segment AB. Arcs have been created above and below the segment from points A that are equidistant from point A. The compass was kept at the same distance, placed on point B, and two additional arcs were created above and below the segment that intersect with the first arcs created. The intersection of the arcs above the segment created point C. The intersection of the arcs below the segment created point D. A line was drawn from point C to D through the segment.

Does the construction demonstrate how to bisect a segment correctly by hand?

A. Yes; the compass was kept at the same width to create the arcs for points C and D.

B. Yes; a straightedge was used to create segment CD.

C. No; the compass was not kept at the same width to create the arcs for points C and D.

D. No; a straightedge was used to create segment CD.

7 0
2 years ago
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