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Over [174]
3 years ago
9

In this stoichiometry problem, determine the limiting reactant.

Chemistry
1 answer:
Tanya [424]3 years ago
8 0

Answer:

Limiting reactant is NiSO₄

Explanation:

The reaction of aluminum metal with aqueous nickel(II)  sulfate to produce aqueous aluminum sulfate and nickel is:

2 Al(s) + 3 NiSO₄ → Al₂(SO₄)₃ + 3 Ni  

<em>That means 2 moles of Al react with 3 moles of nickel sulfate.</em>

<em />

Moles of Al and NiSO₄ are:

Al: 108g × (1mol / 26.98g) = 4.00 moles of Al

NiSO₄: 464g × (1mol / 154.75g) = 3.00 moles of NiSO₄

For a complete reaction of aluminium there are necessary:

4.00mol Al ₓ ( 3 moles NiSO₄ / 2 moles Al) = 6 moles of NiSO₄

As you have just 3.00 moles of NiSO₄, the <em>limiting reactant is NiSO₄</em>

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The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
ziro4ka [17]

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ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

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See explanation.

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