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Reptile [31]
3 years ago
5

Formular for solubility​

Chemistry
2 answers:
Komok [63]3 years ago
6 0

Answer:

= konstanta produk kelarutan

= kation dalam larutan berair

= anion dalam larutan berair

= konsentrasi relatif a dan b

DARI WEB

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g . Solubility of NaNO3=21.9g or NaNO3 x 100 g/ 25 g =87.6. Calculate the molar mass of the dissolved compound as the sum of mass of all atoms in the molecule.

Korvikt [17]3 years ago
3 0

Answer:

K_{sp} = [A^+]^a [B^-]^b

K_{sp} = solubility product constant

A^+ = cation in an aquious solution

B^- = anion in an aqueous solution

a, b = relative concentrations of a and b

Explanation:

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2 years ago
A student preforms a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the m
tatuchka [14]

Answer:

Mass of water = 73.08 g

Explanation:

Given data:

Mass of hydrogen = 35 g

Mass of oxygen = 65 g

Mass of water = ?

Solution:

First of all we will write the balanced chemical equation:

2H₂  + O₂   →    2H₂O

Number of moles of hydrogen = mass/ molar mass

Number of moles of hydrogen =  35 g/ 2 g/mol

Number of moles of hydrogen = 17.5 mol

Number of moles of oxygen = 65 g / 32 g/mol

Number of moles of oxygen = 2.03 moles

Now we compare the moles of water with moles hydrogen and oxygen.

                                     H₂               :              H₂O

                                      2                :                2

                                    17.5              :              17.5

                                       O₂             :            H₂O

                                      1                :               2

                                      2.03         :             2× 2.03 =4.06 mol

Number of moles of water produced by oxygen are less so oxygen is limitting reactant.

Mass of water:

           Mass of water = number of moles × molar mass

          Mass of water = 4.06 mol × 18 g/mol

           Mass of water = 73.08 g

8 0
3 years ago
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