Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
1.object pronoun
2subject pronoun
3reflexive pronoun 4.object pronoun
Answer:
Solving the inequality we get x>-9.33
The graph is shown in figure attached.
Step-by-step explanation:
We need to solve the inequality: 
Solving:
Switching the sides , reversing the inequality and Multiply 3 with terms inside the bracket
Subtract 6 from both sides
Divide both sides by -3 and inequality will be reversed
Solving the inequality we get x>-9.33
The graph is shown in figure attached.
Step-by-step explanation:
plug in y
6=1/3x+11/15
multiply both sides by 15 to get rid of the fraction
90 = 5x +11
move terms to make them like terms
-5x =11- 90
-5x = -79
divide both sides by -5
evaluate for x
