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OleMash [197]
3 years ago
8

What is the distance, in units, between the points (3, -2) and (7, 5)?

Mathematics
2 answers:
AlexFokin [52]3 years ago
3 0

Answer:

Step-by-step explanation:

Hope it helped

BabaBlast [244]3 years ago
3 0

Answer:

√65 (units)

Step-by-step explanation:

A(3, -2) and B(7, 5)

AB=√ [(xB-xA)²+(yB-yA)²]

AB=√ [(7-3)²+(5+2)²]=√(16+49)

AB=√65 (units)

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I dont get how to do this one
harina [27]

Answer:

x is gonna be 10 and y is gonna be 7 and 15

3 0
3 years ago
Which of these is the algebraic expression for "4 times the sum of 2 and y?" (1 point) 4 ⋅ 2 + y 4(2 + y) 2 + 4 ⋅ y 2(4 + y)
Tom [10]

The correct choice is the second one which is 4(2 + y)

5 0
4 years ago
Read 2 more answers
A town's speed limit is 25 miles per hour. Manny received a citation for driving too fast. If Manny was driving 36 percent over
LuckyWell [14K]

Answer:

34 mph

Step-by-step explanation:

  • Firstly we will take 36% of 25 by following formula                                                    36/100 ×25
  • We will get the answer 9                                                                            
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8 0
3 years ago
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I need help on the Math question?
mrs_skeptik [129]

Answer:

The answer is D.

Step-by-step explanation:

3x*3x = 9x^2

3x*2= 6x

5*3x=15x

5*2=10

6x+15x=21x

9x^2+21x+10

3 0
3 years ago
12. A research study was conducted to estimate the number of white perch (a type of fish) in a Midwestern lake. 300 perch were c
Artyom0805 [142]

Answer:

If the scientist’s estimate about the number of fish in the lake is correct, then it is 44% likely to get 20 perch out of 50 with a tag.

Step-by-step explanation:

Let p be the proportion of tagged white perch in the Midwestern lake.

Scientist's claim is that p=\frac{300}{1000} =0.30

Let's test this hypothesis as:

  • H_{0}: p=0.30
  • H_{a}: p≠0.30

P-value of the test statistic will give the likelihood of getting 20 perch out of 50 with a tag if the scientist's estimate (H_{0}) is true.

Test statistic can be calculated using the equation

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of white perch  (\frac{20}{50} =0.25)
  • p is the proportion assumed under null hypothesis. (0.30)
  • N is the sample size (50)

Then z=\frac{0.25-0.30}{\sqrt{\frac{0.30*0.70}{50} } }≈ -0.77

Two tailed p-value of the test statistic is ≈ 0.44

Thus if the scientist’s estimate about the number of fish in the lake is correct, (p=0.30) then it is 44% likely to get 20 perch out of 50 with a tag.

4 0
3 years ago
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