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dsp73
3 years ago
9

PLZ HELP ASAP...Write the equation of a line a slope intercept form Slope= -4 Point = (2,-4)

Mathematics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

y=-4x+4

Step-by-step explanation:

equation of a line: y=mx+b (m:slope, b: y-intercept)

m=-4 (given)

y=-4x+b

substitute with (2, -4): -4=(-4)(2)+b

solve for b: -4=-8+b, b=4

y=-4x+4

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Step-by-step explanation:

Use the coordinates of the given points to find the slope.

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difference in x-coordinates = 2 - (-1) = 3

slope = -9/3 = -3

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the image is upside down

Step-by-step explanation:

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Troyanec [42]

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3 years ago
Which set of side lengths forms a right triangle?
pochemuha

Awnser:

9,12,18

Step-by-step explanation:

you have to add the smallest numbers together and it has to be greater that the greatest number.

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3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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