Question

Drag each tile to the correct box. Consider the given functions f, g, and h.

Answer 1

Answer:

g, f, h

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

So, in your case, we want to compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,$\quad h(0)=0^2+0-6=-6$

And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

Answer 2

Answer:

his answer is write i had it on a quiz and that was the right answer

Step-by-step explanation: