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GaryK [48]
2 years ago
15

What type of angles are these?

Mathematics
2 answers:
Alchen [17]2 years ago
4 0

Answer:

adjacent angle

Step-by-step explanation:

a linear pair =180 so not it

supplementary and complementary can't be it either due to neither being right angles

not a vertical angle

right next to each other with a common line to connect them so adjacent angle

True [87]2 years ago
3 0

Answer:

The one in the picture is called an acute angle which is under 90°

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6x+3-(8x-5)
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Grandpa schmidt is 75 years old. this is 9 years less than seven times the age of junior schmidt. how old is junior
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Step-by-step explanation:

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A ray and a line intersect to form ∠1 and ∠2 as shown below.
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STEP 3

Step-by-step explanation:

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
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