Question

The image above shows a rigid container filled with gas at a temperature of 300 k and a pressure of 10.0 atm. If the temperature increases to 320 k, what is the new pressure of the container?

Answer 1

Answer:

Pressure = 10.67atm

Explanation:

Initial temperature (T1) = 300k

Initial pressure (P1) = 10.0atm

Final temperature (T2) = 320K

Final pressure (P2) = ?

This question involves the use of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided that its volume remains constant

Mathematically,

P = kT = P1 /T1 = P2 / T2 = P3 /T3=........=Pn/Tn

P1 / T1 = P2 / T2

Solving for P2

P2 = (P1 * T2) / T1

P2 = (10 * 320) / 300

P2 = 10.67atm

The pressure of the gas is 10.67atm

Answer 2

Answer:

$P_{2} = 10.667\,atm$

Explanation:

Let suppose that gas behaves ideally and experiments isothermal processes. Then, the following relationship is used:

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$P_{2} = P_{1}\cdot \left(\frac{T_{2}}{T_{1}} \right)$

$P_{2} = (10\,atm)\cdot \left(\frac{320\,K}{300\,K} \right)$

$P_{2} = 10.667\,atm$