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slava [35]
2 years ago
14

Carbon dioxide and water are produced when ethanol, C2H5OH, is burned in oxygen. The number of moles of CO2 that is produced whe

n burning 6.0 mol of ethanol is
Chemistry
1 answer:
suter [353]2 years ago
7 0

The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

We can see that every 1 mole of ethanol we will get 2 mole of CO₂.

So 6.0 mol of ethanol we will get = 6.0 × 2.0

                                                       = 12 mol of CO₂

Thus from the above conclusion we can say that The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ1

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A block of iron has a mass of 150 g and a volume of 20 ml. What is the density of iron? *
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<h3>The answer is 7.50 g/mL</h3>

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density =  \frac{mass}{volume} \\

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volume = 20 mL

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density =  \frac{150}{20}  =  \frac{15}{2}  \\

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<h3>7.50 g/mL</h3>

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What characterizes a heterogeneous mixture?
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What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0
3 years ago
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