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slava [35]
1 year ago
14

Carbon dioxide and water are produced when ethanol, C2H5OH, is burned in oxygen. The number of moles of CO2 that is produced whe

n burning 6.0 mol of ethanol is
Chemistry
1 answer:
suter [353]1 year ago
7 0

The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

We can see that every 1 mole of ethanol we will get 2 mole of CO₂.

So 6.0 mol of ethanol we will get = 6.0 × 2.0

                                                       = 12 mol of CO₂

Thus from the above conclusion we can say that The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ1

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Viktor [21]

Answer: The equation is written below.

Explanation:

2PO_4^{3-}(aq)+Al_2(SO_4)_3(aq)\rightarrow 2AlPO_4(s)+3SO_4^{2-}(aq)

According to Stoichiometry of the reaction:

2 moles of phosphate ions reacts with 1 mole of aluminum sulfate to produce 2 moles of aluminum phosphate precipitate and 3 moles of sulfate ions.

Aluminum phosphate is an odorless and white crystalline solid

The chemical equation is written above.

8 0
2 years ago
3.75 g of an unknown gas at 59 °C and 1.00 atm is stored in a 1.35-L flask. What is the molar mass of the gas?
MAXImum [283]
You need to find moles of the gas, so you would use the ideal gas law:
PV=nRT
Pressure
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n=moles
R= gas constant
Tenperature in Kelvin
n= PV/RT
(1.00atm)(1.35L)/(.08206)(332K) = 0.050mol
Molar mass is grams per mole, so
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4 0
3 years ago
The blood cells that directly attack germs are: *​
irga5000 [103]

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Decide which element probably has a boiling point most and least similar to the boiling point of cesium.
natka813 [3]

Answer:

Take a look at the attachment below

Explanation:

Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

<em>Hope that helps!</em>

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