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kumpel [21]
2 years ago
12

A rectangle is 10 inches wider than it is long. The perimeter is 48 inches. what is the length and width of the rectangle?

Mathematics
1 answer:
Liula [17]2 years ago
3 0

Answer:

a) x represents length?

b) 10+x=48

d) 38 inches

Step-by-step explanation:

c) 10+x=48

subtract 10 to both sides

x=48-10

x=38

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The sum of two integers is -13. Their difference is 7. What are the two integers?
Darya [45]
The two integers are -3 and -10
7 0
3 years ago
A kayaker travels x miles per hour downstream for 4 hours. On the 6-hour return trip, the kayaker travels 2 mile per hour slower
Stolb23 [73]

                              time       *      rate          =       distance

Downstream           4           *       x              =          4(x)

Upstream                6           *     x - 2           =        6(x - 2)

distance downstream = distance upstream:

                              4(x) = 6(x - 2)

                               4x  = 6x - 12

                              -2x  =   -12

                                 x   =    6

Distance Upstream: 4x   = 4(6)   = 24

Distance Upstream: 6(x - 2)  = 6(6 - 2)   = 6(4)   = 24

Total distance traveled is Upstream + Downstream = 24 + 24 = 48

Answer: 48 miles

5 0
3 years ago
Help quick! I'll mark your answer as the brainliest if your answer is correct!
Anna007 [38]

Answer:

They would never intersect because they are parallel lines. You can tell they are parallel lines because they have the same slope and they have a different y-intercept. However, this doesn't mean that there was no solutions, there were, thats how i was able to tell what their slopes and y-intercepts were. So if there is an answer that you can choose from that explains that they won't intersect because they are parallel then that is the correct answer. It may be C, but I would see if there is another option.

8 0
2 years ago
Pls help I’ll brainlest
svet-max [94.6K]

Answer:

Choice B

Step-by-step explanation:

7.1×10⁵ = 710,000

8 0
2 years ago
Read 2 more answers
Evaluate the following limit:
Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

                            \large\displaystyle\text{$\begin{gathered}\sf L  = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4  }{x^{3}-5  }  \end{gathered}$}\\

                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0
1 year ago
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