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kumpel [21]
3 years ago
12

A rectangle is 10 inches wider than it is long. The perimeter is 48 inches. what is the length and width of the rectangle?

Mathematics
1 answer:
Liula [17]3 years ago
3 0

Answer:

a) x represents length?

b) 10+x=48

d) 38 inches

Step-by-step explanation:

c) 10+x=48

subtract 10 to both sides

x=48-10

x=38

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Emma buys packets of coloured beads.
Black_prince [1.1K]

Answer:

5 purple beads

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4 blue beads

Step-by-step explanation:

Find the common factor of 8 5 and 10

Which is 40

8 * 5 = 40

5 * 8 = 40

4 * 10 = 40

8 0
3 years ago
What is the slope of a line parallel to the line whose equation is x-6y = 42. Fully reduce your answer.
Maksim231197 [3]
The slop would be 1/6.

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4 0
3 years ago
How do you find the perimeter
lukranit [14]

The perimeter is 86 m.

When you add the 18 with the 11, you get the length of the bottom side, which is 29. When you add the nine and the 6, you get the length of the left side, which is 15. Now add everything together.

18 + 6 + 11 + 9 + 29 + 15 = 86 m

Hope I helped. Good luck!! : )

4 0
3 years ago
Steve puts an 18-foot ladder against his house. The ladder reaches a height of 15 feet on the house. How far is the bottom of th
krek1111 [17]

Answer:

3 \sqrt{11}

Step-by-step explanation:

Since we are given the hypotenuse which is 18 since it slanted, and leans on the house. And we are given one of the legs which is 15 since it is vertical. We can use the pythagorean theorem to solve for this problem.

{a}^{2}  +  {b}^{2}  = c {}^{2}

where a and b are the legs and c is the hypotenuse l.

Let plug it in

{a}^{2}  + 15 {}^{2}  =  {18}^{2}

{a }^{2}  + 225 = 324

{a}^{2}  = 99

a =  \sqrt{99}

a =  \sqrt{9 \times 11}

a = 3 \sqrt{11}

4 0
3 years ago
Evaluate 4r(t – v) if r = 3, t = 5, and v = 2.
V125BC [204]
4r(t-v) r=3, t=5, and v=2
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12(3)
36
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3 years ago
Read 2 more answers
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