see the attached figure to better understand the problem
we know that
1) If angle 1 and angle 2 are complementary angles
then
m∠1+m∠2= ------> equation A
2) If angle 1 and angle 2 are congruent angles
then
m∠1=m∠2 ------> equation B
Substitute equation B in equation A
m∠1+(m∠1)=
2m∠1=
m∠1=
therefore
<u>the answer is</u>
Answer:
(a-1) 22 rookies receiving a rating of 4 or better.
(a-2) 14 rookies received a rating of 2 or worse.
(b-1) Constructed below in explanation.
(b-2) 8% of total rookies received a rating of 5.
Step-by-step explanation:
We are provided the rating of Fifty pro-football rookies on a scale of 1 to 5 based on performance at a training camp as well as on past performance.
The frequency distribution constructed is given below:
Rating Frequency
1 4
2 10 where ranking of 1 indicate a poor prospect whereas
3 14 ranking of 5 indicate an excellent prospect.
4 18
5 4
(a-1) Rookies receiving a rating of 4 or better = Rating of 4 + Rating of 5
So, by seeing the frequency distribution 18 rookies received a rating of
4 and 4 rookies received a rating of 5.
Hence, Rookies receiving a rating of 4 or better = 18 + 4 = 22 rookies.
(a-2) Number of rookies received a rating of 2 or worse = Rating of 2 +
Rating of 1
So, by seeing the frequency distribution 10 rookies received a rating of
2 and 4 rookies received a rating of 1.
Hence, Rookies receiving a rating of 2 or worse = 10 + 4 = 14 rookies.
(b-1) Relative Frequency is calculated as = Each frequency value /
Total Frequency
Rating Frequency(f) Relative Frequency
1 4 4 / 50 = 0.08
2 10 10 / 50 = 0.2
3 14 14 / 50 = 0.28
4 18 18 / 50 = 0.36
5 <u> 4 </u> 4 / 50 = 0.08
<u>= 50 </u>
Hence, this is the required relative frequency distribution.
(b-2) To calculate what percent received a rating of 5 is given by equation :
<em> x% of 50 = 4 </em> {Here 4 because 4 rookies received rating of 5}
x = = 8% .
Therefore, 8% of total rookies received a rating of 5.