Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
1:50 PM
Step-by-step explanation:
Left school at 10:38 AM,
took them 51 minutes,
38+51=89,
89-60=29,
so when they drove to the museum, it was 11:29 AM.
From here, they stayed at the museum for 1 hour and 26 minutes,
so they stayed at the museum until 12:55 AM since 29+26=55.
Now, it took them 55 minutes to drive back to the school,
so 12:55 plus another 55 minutes,
it's going to be 1:50 PM when Dale's class got back to school.
horizontal shrink by a factor of 1/2
4 units to the left
Answer:
-1.85 -7/8 1 3/4
Step-by-step explanation:
It is about which one is to the farest right ▶️ from 0
Equation: f(x)=(1/5)x^2 or f(x)=(0.2)x^2
Check:
f(0)=(1/5)(0)^2
f(0)=(1/5)(0)
f(0)=0✓
f(5)=(1/5)(5)^2
f(5)=(1/5)(25)
f(5)=5✓
