Answer:
The correct answer is 25.2 in.
Step-by-step explanation:
It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.
2 inches of the ribbon are frayed so actual length = 58 inches
Please refer to the attached image for the ribbon.
A is at 0
C is at 60
B is at 2
P is the point to divide the remaining ribbon in the ratio 2:3.
Part AB of the ribbon is frayed.
BP: PC = 2:3
Let BP = 2
and PC = 3
Now, BP + PC = BC = 58 = 2 + 3 = 5
So,
BP = 
Location of the Cut = 2 + 23.2 = <em>25.2 inches</em>
<em></em>
Alternatively, we can use the formula directly:
m: n is the ratio 2:3
Answer:
B) 4
Step-by-step explanation:
Tan is opposite/adjacent. That means that 3 is the opposite side while 4 is the adjacent side.
22 increases by 0.9
24 increases by 4 and 1/2
25 increases by 4.3
Just subtract the number from the number after it to find how to find the next numbers in the sequence
Answer: 6x + $2= $21.50
Step-by-step explanation:
To make an equation first we are going to give the cost of each taco the variable x since we don't know what it is. Then we will combine 6 multiplied by x to get 6x and add it to $2 to get $21.50 so the equation will be 6x + $2= $21.50. First we subtract 2 from both sides of the equation which makes the equation become 6x= $19.50. Then we divide both sides of the equation by 6 and get x=$3.25. This means that each taco cost $3.25.
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
