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forsale [732]
3 years ago
8

Suppose that you and a friend are playing cards and decide to make a bet. If you draw three face cards, where a face card is a J

ack, a Queen, or a King, in succession from a standard deck of 52 cards without replacement, you win $40. Otherwise, you pay your friend $10. What is the expected value of your bet? Round your answer to the nearest cent, if necessary.
Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Expected value of the bet =

<h3>P(you make the correct draw) * 40 + P(you do not make the correct draw) * (-10) = </h3>

(4/52)(4/51)(4/50) * 40 + (1 - (4/52)(4/51)(4/50)) * (-10) =

(64/132600) * 40 + (1 - 64/132600) *(-10) =

64/3315 + (132536/132600) * (-10) =

64/3315 - (132536/13260) =

64/3315 - 33134/3315 =

-33070/3315 =

-9.97586726998 =

-$9.98, rounded to the nearest cent  

(i.e., the expected value of the bet is a loss of $9.98)

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6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
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Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

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h the height of the ballonist above the ground,

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a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

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S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

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S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

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