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2 years ago

Please help with solving

Mathematics

1 answer:

Makovka662 [10]2 years ago

4 0

N.O = 4
N is midpoint of M.0
Meaning M.N also has to be 4
4+4= 8
N.P = 6
0.P = 2
8+ 2 = 10

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Which system of equations below has infinitely many solutions? y = –3x 4 and y = –3x – 4 y = –3x 4 and 3y = –9x 12 y = –3x 4 and

Flura [38]

the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Condition for the parallel lines.

L1, ax + bx + c = 0

L2, dx + ey + f = 0

If $\rm \dfrac{a}{d} = \dfrac{b}{e} = \dfrac{c}{f}$ then lines have infinitely many solutions.

<h3>Which system of equations below has infinitely many solutions?</h3>

y = –3x + 4 and 3y = –9x + 12

On comparing we have

a = -3 , b = 1, and c = 4

d = -9 , e = 3, and f = 12

Then their ratio will be

$\rm \dfrac{1}{3} = \dfrac{-3}{-9} = \dfrac{4}{12}\\\\\rm \dfrac{1}{3} = \dfrac{1}{3} = \dfrac{1}{3}$

Hence y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.

Thus the option B is correct.

More about the linear system link is given below.

brainly.com/question/20379472

7 0

2 years ago

Colin buys a tv for £530. It depreciates at a rate of 3% per year. How much will it be worth in 5 years? Give your answer to the

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Answer: In 5 years it will be worth £455

Step-by-step explanation:

Step 1

Given

The cost of the T.V. for Colin = £530.

The rate of depreciation per year = 3%

Time/ period = 5 years

Formulae to be used

F = P X (1 - r) ^ n

where

F = the future value after depreciation

P = the present value.

r =the interest rate per time period

n = the time/ periods

Step 2--- SOLVING

F = P X (1- r) ^ n

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=530 x 0.858734

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Rounding up to the nearest penny where appropriate = £455

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3 years ago

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Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

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so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

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Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

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Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

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we can plug values

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now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

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