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deff fn [24]
4 years ago
13

There are 25 students in the school's Pep Club.

Mathematics
1 answer:
VashaNatasha [74]4 years ago
7 0

Answer:

company b 10,080 dollars

Step-by-step explanation:

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Want brainlyest? Please help me. :)))) and I swear I will!!!
guajiro [1.7K]

Answer:

5/8 so, it is a fraction

Step-by-step explanation:

there is 5 out of 8 shaded

4 0
3 years ago
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Jose earns $3680 per month, of which 22% is taken out for federal and state income taxes and other required deductions. Last mon
zzz [600]

Answer: 30%

Step-by-step explanation:

Firstly, we find 22% of $3680. This will be:

= 22% × $3680

= 0.22 × $3680

= $809.60

Therefore, his take home pay will be:

= $3680 - $809.60

= $2870.40

We are further told that last month he spent $775 for rent and 86.12 on clothing. The amount combined will be:

= $775 + $86.12

= $861.12

The percent of his take-home pay did he spend on rent and clothing combined will be:

= 861.12 / 2870. 40 × 100

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3 0
3 years ago
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The function g has an inverse. The function g − 1 determines the number of folds needed to give the folded paper a thickness of
Amanda [17]

Answer:

\mathbf{g^{-1} (t) = log _2  \ 20 \ t}

Step-by-step explanation:

Here is the full question

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.

Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

g(n )= (05)2^n

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).

<u>SOLUTION:</u>

If we represent g(n) with  t;

Then

\mathbf{t = (0.05)2^n} \\ \\ \mathbf{\dfrac{t}{0.05} = 2^n} \\ \\ \mathbf{\dfrac {100 \ t }{ 5} = 2^n} \\  \\ \mathbf{20 t = 2^n}

Taking logarithm of both sides; we have :

\mathbf{log (20 t) = n log 2}    \ \ \    \mathbf{(since  \ ,  log  \ a^b = b \ log \ a) }  \\ \\ \mathbf{n =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) = log _2  \ 20 \ t}

4 0
4 years ago
For your parent’s 25th wedding anniversary, you want to restore and enlarge their engagement picture. The photo was originally 3
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I believe the answer would be 60 in high
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1. How many Grade 10C students should join so that they can fill the quota? (Show your computation).​
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You have to put the b is
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