If two similar triangles have side lengths 3cm and 7cm then we can determine that the scale factor for the lengths is: 7/3
Now, we have to work out the area scale factor !
This is simple, since area is given in cm² then all we have to do is square our original scale factor!
So,
7/3² = 49/9
So, we can say that the ratio of the area would be:
x : 49/9x
Hope this helps! <3
Answer:
See below:
Step-by-step explanation:
Hello! We can check to see if the inequality is true by replacing r with 18 as we have been told to find them in which 18 as r makes the equation true.
So our equations to test for are:
We can input 18 as r and then we see the following are correct:
1. No, as a -21 is not greater than -6
2. Yes, as -15 is less than 6.
3. No, as 21 is not greater than 6
4. No, as -15 is not greater than 6.
Cheers!
Answer:
1) log7 (5*8)= log7(40)
2) log2(11) -log2(9)=log2(11/9)
3)2log9 2=log9(2^2)
The common ratio in the geometric sequences 2
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Answer:
See explanation.
Step-by-step explanation:
We are looking at a geometric distribution.
The probability of selecting a brown peanut is .12 = p
The probability of not selecting a brown peanut is .88 = q
The probability mass function is p(y) = (.88)^(y-1) * (.12)
a) p(7) = (.88)^6 * .12 = .0557
b) p(7 <= y <= 8) = p(7) + p(8)
= .0557 + (.88)^7 * .12 = .1048
c) p(y <= 7) = p(0) + p(1) + ... + p(7)
= .12 + (.88)^1 * .12 + (.88)^2 * .12 + ... + (.88)^6 * .12 = .4713
d) The expect value is 1/p. So, 1/(.12) = 8.33 M&M's
