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Nostrana [21]
3 years ago
12

Which are real zeroes of this function? x3 + 2x2 – 9x – 18

Mathematics
1 answer:
stepan [7]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

E. -2, 3, -3

<h2>Why?</h2>

To find the zeroes of the function, we just need to evaluate the given values and check if the function/expression tends to 0.

We are given the function

f(x)=x^{3}+2x^{2}-9x-18

Now, to find the zeroes, we need to substitute the values, so, substituting the values of the option E, we have:

First value, -2:

f(-2)=-2^{3}+2*(-2)^{2}-9*(-2)-18

f(-2)=-8+2*4+18-18

f(-2)=-8+8+18-18=0

Second value, 3:

f(3)=3^{3}+2*(3)^{2}-9*(3)-18

f(3)=27+2*9-27-18

f(3)=27+18-27-18=0

Third value, -3:

f(-3)=-3^{3}+2*-3^{2}-9*-3-18

f(-3)=-27+2*9+27-18

f(-3)=-27+2*9+27-18=0

Hence, we have that evaluating the values of the option E, the function tends to 0.

So, the correct option is: E. -2, 3, -3

Have a nice day!

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