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madreJ [45]
3 years ago
14

IF YOU ANSWER ALL THE QUESTIONS THEN I WILL GIVE YOU BRAINEST!!! 20 POINTS!!!!

Physics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

1.) A,     2.) D,     3.) C

Explanation:

Hope this Helps! :D

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The sound wave is 1.0 meters

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A two-liter bottle of your favorite beverage has just been removed from the trunk of your car. The temperature of the beverage i
Ksivusya [100]

Answer:

a) 209.3 kilojoules must be removed from two liter of beverage, b) A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles, c) Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Explanation:

a) <em>How much heat energy must be removed from your two liters of beverage?</em>

At first we suppose that the beverage has the mass and specific heat of water and that there are no energy interactions between the bottle and its surroundings.

From the First Law of Thermodynamics and definition of sensible heat, we get that amount of removed heat (Q), measured in kilojoules, is represented by the following formula:

Q = \rho \cdot V\cdot c\cdot (T_{o}-T_{f}) (Eq. 1)

Where:

\rho - Density of the beverage, measured in kilograms per cubic meter.

V - Volume of the bottle, measured in cubic meters.

c - Specific heat of water, measured in kilojoules per kilogram-Celsius.

T_{o}, T_{f} - Initial and final temperatures, measured in Celsius.

If we know that \rho = 1000\,\frac{kg}{m^{3}}, V = 2\times 10^{-3}\,m^{3}, c = 4.186\,\frac{kJ}{kg\cdot ^{\circ}C}, T_{o} = 35\,^{\circ}C and T_{f} = 10\,^{\circ}C, then:

Q = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (2\times 10^{-3}\,m^{3})\cdot \left(4.186\,\frac{kJ}{kg\cdot ^{\circ}C} \right) \cdot (35\,^{\circ}C-10\,^{\circ}C)

Q = 209.3\,kJ

209.3 kilojoules must be removed from two liter of beverage.

b) <em>You are having a party and need to cool 10 of these two-liter bottles in one-half hour. What rate of heat removal, in kW, is required?</em>

The total amount of heat that must be removed from 10 2-L bottles is:

Q_{T} = 10\cdot (209.3\,kJ)

Q_{T} = 2093\,kJ

If we suppose that bottles are cooled at constant rate, then, rate of heat removal is determined by this formula:

\dot Q = \frac{Q_{T}}{\Delta t} (Eq. 2)

Where:

Q_{T} - Total heat, measured in kilojoules.

\Delta t - Time, measured in seconds.

\dot Q - Rate of heat removal, measured in kilowatts.

If we know that Q_{T} = 2093\,kJ and \Delta t = 1800\,s, we find that rate of heat removal is:

\dot Q = \frac{2093\,kJ}{1800\,s}

\dot Q = 1.163\,kW

A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles.

c) <em>Assuming that your refrigerator can accomplish this and that electricity costs 8.5 cents per kW-hr, how much will it cost to cool these 10 bottles (in $)?</em>

A kilowatt-hour equals 3600 kilojoules. The electricity cost is equal to the  removal heat of 10 bottles (Q_{T}), measured in kilojoules, and unit electricity cost (c), measured in US dollars per kilowatt-hour. That is:

C = c\cdot Q_{T}

If we know that c = 0.085\,\frac{USD}{kWh} and Q_{T} = 2093\,kJ, the total cost of cooling 10 bottles is:

C = \left(0.085\,\frac{USD}{kWh}\right)\cdot \left(2093\,kJ\right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ}  \right)

C = 0.049\,USD

Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

3 0
4 years ago
An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in
Vsevolod [243]

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

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Which two options describes behaviors of particles that are related to the chemical properties of the materials
jarptica [38.1K]

Answer:

The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.

Explanation:

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3 years ago
KmCL`MSMCMMXMMXMXMMX WHAT ARE THE consequences OF A VOLCANO
DerKrebs [107]

Answer:

Fast-moving lava can kill people and falling ash can make it hard for them to breathe. They can also die from famine, fires and earthquakes which can be related to volcanoes. People can lose their possessions as volcanoes can destroy houses, roads and fields. Lava can kill plants and animals too.

Explanation:

Hope this helps :)

Brainliest?

4 0
3 years ago
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