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wariber [46]
3 years ago
7

A teacup on a spinning teacup ride takes 1.5 s to complete a revolution around the center of the platform. What is the centripet

al acceleration of the teacup if it is 3.0 m from the center of the ride?
Physics
2 answers:
deff fn [24]3 years ago
6 0

Answer:

Centripetal acceleration, 52.6 m/s²

Explanation:

It is given that,

A teacup on a spinning teacup ride takes 1.5 s to complete a revolution around the center of the platform.

Distance covered by the particle in circular path is, d=2\pi r

We have to find centripetal acceleration of the teacup, a_c=\dfrac{v^2}{r}

Where, v is the velocity v=\dfrac{2\pi r}{t}

a_c=\dfrac{4\pi^2 r}{t^2}

a_c=\dfrac{4\pi^2\times 3}{(1.5)^2}

a_c=52.6\ m/s^2

Hence, centripetal acceleration of the teacup if it is 3.0 m from the center of the ride is 52.6 m/s²

arlik [135]3 years ago
5 0
The correct answer is 53 meters per second squared 
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A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time
baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

i = \frac{q}{t}

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

i = increased

So correct answer will be

B. The current increases.

4 0
3 years ago
A wheel has a constant angular acceleration of 4.5 rad/s2. during a certain 5.0 s interval, it turns through an angle of 128 rad
dalvyx [7]
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2 
where:Ø - angular displacement w1 - initial angular velocity t - time ã - angular acceleration 
128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1 
w1 = wo + ãt 
w1 - final angular velocity 
wo - initial angular velocity 
18 = 0 + 4.5t t = 4 s
3 0
3 years ago
A lawyer drives from her​ home, located 88 milesmiles east and 1818 milesmiles north of the town​ courthouse, to her​ office, lo
myrzilka [38]

Answer:

the distance between the​ lawyer's home and her office is 124 miles

Explanation:

given information:

first lets assume that

x-axis (west = positive, east = negative)

y-axis (north = positive, south = negative)

thus,

distance of the house = (-88,18)

distance of the office = (13, -54)

thus, the distance between the​ lawyer's home and her office

R = √(x₂ - x₁)² + (y₂ - y₁)²

   = √(13 - (-88))² + (-54 -18)²

   = 124 miles

7 0
3 years ago
What is the rabbit's displacement from t = 0s to 3 s?<br> Answer with two significant digits.
Inessa05 [86]

Answer: i think the answer is 20.0s

Explanation:

3 0
3 years ago
Read 2 more answers
The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele
Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 m/sec^2      

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion v^2=u^2+2as

553^2=0^2+2\times a\times 0.855

a=178835.6m/sec^2

5 0
3 years ago
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