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Alexxandr [17]
2 years ago
9

Explain how you can use equivalent fractions to find the quotient of 2 3 ÷ 4. Sample Response: Find a fraction that is equivalen

t to 2 3 , and has a multiple of 4 as the numerator. Multiply the numerator and denominator by 2 to get 4 6 ÷ 4, since 2 3 = 4 6 . The quotient is 1 6 . Which did you include in your explanation? Check all that apply. Find a fraction that is equivalent to Two-thirds, and has a multiple of 4 as the numerator. Multiply the numerator and denominator by 2.
Mathematics
1 answer:
xz_007 [3.2K]2 years ago
8 0

Answeno

Step-by-step explanation:

sorry

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(x3 + 9x2 + 1)(3x2 + 4x − 4)
kap26 [50]
I don’t understand the question so I answer in two ways

4 0
2 years ago
W= 4/p+2 solve for p
likoan [24]

Answer:

(w-2)x4 = p (i think)

Step-by-step explanation:

8 0
2 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
Round to the nearest hundredth 9.8766
Levart [38]

Answer: 9.88

​​​​​​​​​​​​​​​​​​​

6 0
3 years ago
Read 2 more answers
What is the nth term, if the value of table follows by: 0,1,2,3,5,8..
Vlada [557]

Answer:

13-21-34

Step-by-step explanation:

Fibonacci Sequence:

the next number is found by adding the 2 numbers before it

originally starts off like this:

0-1-1-2-3-5-8-13-21-34

7 0
3 years ago
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