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2 years ago

11

How do you write 1.005 as a mixed fraction

2 answers:

bezimeni [28]2 years ago

8 0

1 1/<span>200 should be the answer</span>

alisha [4.7K]2 years ago

4 0

1 as the whole number and then next to it as a fraction the number 5 over 1000 or 5/1000

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Whenever you sign a lease for an apartment, you typically have to pay a security deposit before you even move in; this is in cas

likoan [24]

The answer is F(x) = 900x + 600

Let x stands for the number of months

The apartment is rented for $900 a month, so every month it will be paid 900x (for example, for one month (x = 1), you will pay 900 · 1 = $900, for three months (x = 5), you will pay 900 · 5 = $4500, etc.)

A security deposit is paid only once and is not dependent on the number of months. So, its value is only 600.

These two values must be summed up because both must be paid, nothing is to subtract. Therefore, the function f(x) for apartments that rent for $900 a month and a security deposit of $600 is:
f(x) = 900x + 600

7 0

3 years ago

Help me with this problem

sveta [45]

Answer:

ñññññññññ

Step-by-step explanation:

11/9/2001

6 0

2 years ago

There are 60 apples and then add 59 apples two times . How many apples and there altogether

STALIN [3.7K]

Answer:

Step-by-step explanation:

59 apples two times = 59 x 2 = 118 apples

Total apples = 118 + 60 = 178 apples

7 0

2 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers

What is the slope of the line shown below?<br> A. -5<br> B. 5<br> C.-2<br> D. 2

expeople1 [14]

Answer:

D. 2

Step-by-step explanation:

rise/run = $\frac{y_{2} -y_1}{x_{2} -x_1} }$ = $\frac{7 - -3}{3- -2}$ = 10/5 = 2

8 0

2 years ago