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Rzqust [24]
3 years ago
10

The question is in the picture.

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:

1. 3sqrt(2)

Choice C

2. 2sqrt(3)

Choice D

Step-by-step explanation:

1.  sqrt(x+3)

sqrt(15+3)

sqrt(18)

sqrt(9*2)

sqrt(9)sqrt(2)

3sqrt(2)

Choice C


2.  6/sqrt(x)

6/sqrt(3)

no radicals in the denominator, multiply by 1 in the form of the radical

6/sqrt(3) * sqrt(3)/sqrt(3)

6sqrt(3)/ (sqrt(3)*sqrt(3))

6sqrt(3)/3

2sqrt(3)

Choice D


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Answer:

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Answer:

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Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

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Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

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Solving for P(S)

The question implies a probability without replacement;

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P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

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