Answer:
false
Step-by-step explanation:
Since this is a fairly small equation, it's pretty easy to plug in a few points to get ordered pairs and sketch a graph:
when x = 0...
f(0) = 2(0)^2
f(0) = 0
(0, 0)
when x = 1...
f(1) = 2(1)^2
f(1) = 2
(1, 2)
when x = -1...
f(-1) = 2(-1)^2
f(-1) = 2
(-1, 2)
from there, you can get a rough sketch of the graph just by plotting those points. essentially, it just looks "skinnier" than your typical parabola because the 2 out front makes the curve steeper.
<span>f(x) = (x^2-16) / (x+3)
f(x) has no horizontal asymptote.
Vertical assymptote is x = -3
Dividing the numerator by the denominator gives x - 3 remainder -7. Therefore, the oblique assymptote is x - 3.
</span>
<span>the vertical asymptotes of the function f(x) = (5x + 1) / (x^2 + x - 6) = (5x + 1)/(x - 2)(x + 3) is x = 2 and x = -3.
</span><span>the zeros of the function f(x) = (3x^2 - 3x - 6 ) / (3x - 6)</span> = (3x^2 + 3x - 6x - 6) / (3x - 6) = (3x(x + 1) - 6(x + 1)) / (3x - 6) = (3x - 6)(x + 1)/(3x - 6) = x + 1 is x = -1
<span>the
function f(x) = (x^2 + x - 12) / (x - 3) = (x - 3)(x + 4) / (x - 3) is --> disc = 3, x-int = (-4, 0), y-int = 4? basic shape =
straight line</span>
y = mx + b, where m = slope, and b = y-intercept.
y = 3x + 3
y = 1/2x - 3
y = 1/2x + 3
y = 3x + 1/2
we can eliminate 2 and 4 since the y-intercept in the graph is shown as (0, 3)
This leaves us with
y = 3x + 3 and y = 1/2x+3
m = change in y / change in x
We take any two points on the line to find the slope.
I chose (2, 4), (0, 3)
change in x: 2 - 0 = 2
change in y: 4 - 3 = 1
m = 1/2
This leaves us with the only answer that has the slope of 1/2 and the y-intercept of 3.
option: 3
y = 1/2x + 3
