2H2 + O2 →2H2O
This is a limiting reactant problem in which you need to figure out which reactant is the limiting reactant. You can usually look at the information given and see that hydrogen has the smaller amount of mass used, but it is always good to check that assumption through stoichiometry:
(9.43g H2/2.02g/mol)(2mol H2O/2mol H2)(18.02gH2O/1mol H2O)= 84.1g H2O produced from 9.43g of H2
(12.98g O2/32.00g/mol O2)(2mol H2O/1mol O2)(18.02gH2O/1mol H2O)= 14.6g H2O
So my assumption that hydrogen makes the smaller amount of water is wrong since oxygen (it is the limiting reactant) created the smaller amount of water with 14.6g, so 14.6g is the maximum amount of water that can be formed
The distance traveled by light : 1.86 x 10⁵ miles
Explanation:
Given
speed of light=v=1.86 x 10⁵ miles/s
time=1 s
Required
distance of light travel
Solution
The motion of light can be considered as motion that has a constant velocity so that it can be classified as a straight, regular motion that has no acceleration
Can be formulated
For the distance traveled by light in the above problem becomes:
The type of reaction that will occur with the given compounds is double-replacement where the components of one is replaced by that from another. This is,
K3PO4 + MgCl2 ----> Mg3(PO4)2 + KCl
Balancing the reactant and product sides,
2K3PO4 + 3MgCl2 ---> Mg3(PO4)2 + 6KCl
Answer:
H₂(g) + S(s) → H₂S + 20.6 KJ
Explanation:
The energy changes occur during the bonds formation and bonds breaking.
There ere two types of reaction endothermic and exothermic reaction.
Endothermic reactions:
In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.
For example:
C + H₂O → CO + H₂
ΔH = +131 kj/mol
it can be written as,
C + H₂O + 131 kj/mol → CO + H₂
Exothermic reaction:
In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.
For example:
Chemical equation:
C + O₂ → CO₂
ΔH = -393 Kj/mol
it can be written as,
C + O₂ → CO₂ + 393 Kj/mol
The formation of hydrogen sulfide is exothermic reaction.
H₂(g) + S(s) → H₂S ΔH = -20.6 KJ
It will be written as,
H₂(g) + S(s) → H₂S + 20.6 KJ
Answer:
The classification and illustrations are attached in the drawing.
Explanation:
It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.
On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.