From 5 L to moles, just divide 5 by 22.4. I got 0.22 moles of H2.
From 5 moles to liters, just multiply 5 by 22.4. I got 112 L of H2.
Answer:
The mass of the products left in the test tube will be less than that of the original reactants.
Explanation
The equation for the reaction is
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
1.0 3.0 3.9 0.1
Assume you started with 1.0 g of Mg.
It will react with 3.0 g of HCl to form 3.9 g of MgCl2 and 0.1 g of H2
.
Mass of reactants = mass of products
1.0 g + 3.0 g = 3.9 g + 0.1 g
4.0 g = 4.0 g
The Law of Conservation of Mass is obeyed.
However, your test tube and its contents will weigh 0.1 g less than it did before the reaction.
Does that contradict the Law of Conservation of Mass? It does not.
One of the products was the gas, hydrogen, and it escaped from the test tube. You weren't measuring all the products, so test tube and its contents weighed less than before.
Answer:
108.6 g
Explanation:
- 2NaN₃(s) → 2Na(s) + 3N₂(g)
First we use the <em>PV=nRT formula</em> to <u>calculate the number of nitrogen moles</u>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 0 °C ⇒ 0 + 273.2 = 273.2 K
<u>Inputting the data</u>:
- 1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K
Then we <u>convert 2.5 moles of N₂ into moles of NaN₃</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 2.5 mol N₂ *
= 1.67 mol NaN₃
Finally we <u>convert 1.67 moles of NaN₃ into grams</u>, using its <em>molar mass</em>:
- 1.67 mol * 65 g/mol = 108.6 g
Answer:
The correct option is;
a. The particles will gain a large amount of kinetic energy
Explanation:
As the water temperature reaches 100°C, which is the boiling point for water at atmospheric pressure, the continued heating is then used to break up the strong inter molecular forces between molecules of the water such that the individual molecules are free to move about and due to the high temperature, have gained considerable amount of kinetic energy for the to rise to appreciable height and to also spread.
The heat which converts water into steam is called latent heat as during the boiling phase, the temperature of the water remains constant.
Answer:
B.) 117 g
Explanation:
(Step 1)
To find the mass, you need to first find the moles of NaCl using the molarity ratio.
Molarity = moles / volume (L)
2.00 M = moles / 1.0 L
2.00 = moles
(Step 2)
Now that you know the moles, you can convert it to grams using the molar mass.
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
2.00 moles NaCl 58.443 g
--------------------------- x ----------------- = 117 g NaCl
1 mole
