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larisa [96]
3 years ago
6

What is the difference between 26 and 8

Mathematics
2 answers:
lbvjy [14]3 years ago
6 0

Answer:

the difference is 18

Step-by-step explanation:

Nady [450]3 years ago
4 0
18 because you subtract 8 from 26 and you get the difference
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In a college of exactly 2720 students, exactly 65 % are male. what is the number of female students?
qaws [65]
Multiply 2720 by 65% or 65/100
176800/100 = 1768 This is how many males there are. Now subtract 1768 from 2720 you will get how many females there are
2720-1768 = 952 females
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3 years ago
146, 74, 38, 20, ? what would the next number be in this sequence?
Anuta_ua [19.1K]
Looking at the numbers, we can see that the differences are 72, 36, and 18. Notice that they are each factors of the next by the same constant 2.

18 * 2 = 36
36 * 2 = 72

There, it means that 18/2 will be subtracted from 20.

20 - 18/2
= 20 - 9
= 11

The next number in the sequence would be 11. Hope this helps!
3 0
4 years ago
What is the multiplicative inverse of 10 raise to the power 10​
Alexandra [31]
ESP, answer: at least 5002
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A number is taken away from 40 and the result is 45 What is the number?​
hammer [34]

Answer:

-5

Step-by-step explanation:

<u>Given that , </u>

  • A number is taken away from 40 and the result is 45 .

<u>L</u><u>et </u><u>:</u><u>-</u><u> </u>

  • The required number be x .

<u>According</u><u> to</u><u> Question</u><u> </u><u>:</u><u>-</u><u> </u>

:\implies 40 - x = 45

:\implies - x = 45 - 40

:\implies - x = 5

:\implies x = -5

<h3>Hence the required answer is -5 .</h3>
7 0
3 years ago
The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
marissa [1.9K]

Step-by-step explanation:

Continuous exponential growth model:

population = population(t = 0) \times e ^{ \alpha t}

Where α is the growth rate parameter.

So if t is the starting point and t+t1 is the point that population is doubled:

\frac{population(t + t1)}{population(t)}  = \frac{2 \times population(t)}{population(t)}  = 2 =  {e}^{ \alpha \times t1 }

So:

ln(2)  =  \alpha  \times t1

And as a result, t1, the time needed for the population to double at ANY given point is equal to:

t1 =  \frac{ ln(2) }{ \alpha }

3 0
3 years ago
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