Ask question

Ask question

All categories

3 years ago

6

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 20 N acts on

a certain object, the acceleration
of the object is 4 ms. If the force is changed to 15 N, what will be the acceleration of the object?

1 answer:

miskamm [114]3 years ago

3 0

Answer:

bahihirapan na ako sa module

Step-by-step explanation:

na yan

You might be interested in

What is 6x298 in friendly numbers?

miv72 [106K]

Answer:

The value of 6 * 298 is 1788 and the calculations can be provided as follows:

6 * 298 = 6 * (200 + 90 + 8)

4 0

3 years ago

What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

5 0

3 years ago

Find the slope using the formula LaTeX: \frac{y_2-y_1}{x_2-x_1}y2−y1x2−x1 (9, 10) and (7, 2)

guapka [62]

Answer:

<h2>slope = 4</h2>

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (9, 10) and (7, 2).

Substitute:

$m=\dfrac{2-10}{7-9}=\dfrac{-8}{-2}=4$

7 0

3 years ago

Find the flux of the vector field F = 〈e-z,4z,6xy) across the curved sides of the surface S = {(x,y,z): z= cos y, lys π, 0sxs4}

Len [333]

I'll go ahead and assume you meant to say that <em>S</em> is the surface given by

$S = \left\{(x,y,z) \mid z = \cos(y)\text{ with } 0\le y\le \pi\text{ and }0\le x\le4\right\}$

This immediately gives us a parameterization for the surface,

$\vec r(x, y) = \left\langle x, y, \cos(y)\right \rangle$

The upward-pointing normal vector to this surface is then

$\vec n = \dfrac{\partial\vec r}{\partial x} \times \dfrac{\partial\vec r}{\partial y} = \left\langle0,\sin(y),1\right\rangle$

Then the flux of $\vec F(x,y,z) = \left\langle e^{-z}, 4z, 6xy\right\rangle$ across <em>S</em> is

$\displaystyle \iint_S \vec F(x,y,z)\cdot\mathrm d\vec s = \int_0^4\int_0^\pi \vec F(x,y,\cos(y))\cdot\vec n\,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi \left\langle e^{-\cos(y)},4\cos(y),6xy\right\rangle \cdot \left\langle0,\sin(y),1\right\rangle \,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi (4\sin(y)\cos(y)+6xy)\,\mathrm dy\,\mathrm dx \\\\ = 2 \int_0^4\int_0^\pi (\sin(2y) + 3xy)\,\mathrm dy\,\mathrm dx = \boxed{24\pi^2}$

8 0

3 years ago

Dr black is standing 20 feet from street lamp lamp shadow is 5 feet long angle from top of his shadown to top of light is 30degr

s344n2d4d5 [400]

Then answer would be

90° < 0 < 180°.

hope it helps!

7 0

4 years ago