Answer:
- Option <u><em>d) isotope</em></u>.
Explanation:
All atoms of a same element have equal number of protons (atomic number) but <em>may</em> <em>differ in the number of neutrons.</em>
<em />
The atoms that differ in the number of neutrons are named<em> isotopes</em>.
For example: carbon-12 and carbon-13 are diferent isotopes of the same element, carbon. They have the same number of protons (6, which is the atomic number of carbon). On the other hand, while carbon-12 has 6 neutrons, carbon-13 has 7 neutrons.
As per the other choices:
- a) <em>anions</em> are ions with negative charges: atoms (or group of atoms) that have gained one or more electrons.
- b) <em>cations</em> are ions with positive charge: atoms (or group of atoms) that have lost one or more electrons.
- e) <em>atoms</em> are the individual minimum parts of an element that preserves the properties of such element. All atoms of the same element have the same number of protons and have, essentially, the same chemical properties.
Answer:
19.8 kg of C₂H₂ is needed
Explanation:
We solve this by a rule of three:
If 1251 kJ of heat are relased in the combustion of 1 mol of acetylene
95.5×10⁴ kJ of heat may be released by the combustion of
(95.5×10⁴ kJ . 1) /1251kJ = 763.4 moles of C₂H₂
Let's convert the moles to mass → 763.4 mol . 26 g/1 mol = 19848 g
If we convert the mass from g to kg → 19848 g . 1kg / 1000g = 19.8 kg
Answer:
The answer is B. It contains more non-penetrating solute particles than the interior of the cell.
Explanation:
This means that it has a greater concentration or number of solute particles outside a membrane than there are inside it.
A typical example is Saline solution.
Answer:
The answer to your question is: 516 g of water
Explanation:
2 C₇H₁₄ + 21 O₂ → 14 CO₂ + 14 H₂O
8 moles 43 moles
Process
1.- Find the limiting reactant
Ratio theoretical O₂ / C₇H₁₄ = 21 / 2 = 10.5
Ratio experimental O₂ / C₇H₁₄ = 43 / 8 = 5.3
As the ratio diminishes the limiting reactant is O₂.
2.- Calculate the moles of water
21 moles of O₂ ------------- 14 moles of water
43 moles of O₂ ------------ x
x = (43 x 14) / 21
x = 28.67 moles of water
3.- Calculate the grams of water
Molecular mass of water= 18g
18 g ------------------------ 1 mol of water
x ------------------------ 28.67 moles of water
x = (28.67 x 18) / 1
x = 516 g of water
CH3-CH2-CH2-CH2-CH3
Obtendira lo descrito saludos en tu trabajo