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kodGreya [7K]
3 years ago
13

Explain why the atomic radius of fluorine is smaller than that of lithium​

Chemistry
1 answer:
Sladkaya [172]3 years ago
4 0

1. Common knowledge : Go to the right of periodic table, the atomic radius is decreasing

2. Flurine has 9 protons and lithium has 3 protons. you know that the electron is attracted with the centre of the atom, that's why more proton, more 'energy' that attract to the centre and that's why it make the shape of the atom is smaller

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Match the alkane names and structures.<br> -butane<br> -methane<br> -ethane<br> -propane
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Answer:

Explanation:

Here is the names and matches of butane methane ethane propane

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3 years ago
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The work done to expand a gas is 121 J. During the gas expansion, 402 J of heat is absorbed by the gas sample. Calculate the cha
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Answer: 3.50

Explanation:

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Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p
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Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of Br_2.

\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M

Now we have to calculate the dissociated concentration of Br_2.

The balanced equilibrium reaction is,

                              Br_2(g)\rightleftharpoons 2Br(aq)

Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

As we are given,

The percent of dissociation of Br_2 = \alpha = 1.2 %

So, the dissociate concentration of Br_2 = C\alpha=1.731M\times \frac{1.2}{100}=0.2077M

The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

7 0
3 years ago
28Which is true?
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28) All elements are made of atoms

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-Electrons make up the outside of the Nucleus
8 0
3 years ago
Protons and neutrons are found in the nucleus. these two types of charges are referred to collectively as _____
solmaris [256]

Answer:

Nucleon

Explanation:

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