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Shalnov [3]
1 year ago
15

How do I do this partial pressure problem? (AP CHEM)

Chemistry
1 answer:
RoseWind [281]1 year ago
7 0

The partial pressure of H(g) is 1.07 atm.

<h3>What is the partial pressure?</h3>

We know that the total pressure of a mixture of gases is the sum of the individual pressure of the gases. Now we know from the Dalton law of partial pressure that the total pressure PT = PA + PB + PC + ........

Thus, the molecular hydrogen has a pressure of 2.14 atm and this molecular hydrogen is made to decompose. The partial pressure of each of the H(g) is 2.14/2 = 1.07 atm.

Hence, the partial pressure of H(g) is 1.07 atm.

Learn more about partial pressure:brainly.com/question/13199169

#SPJ1

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Identify, and briefly explain, two key elements needed for fossilization.<br><br>Please Help Me!!!
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The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one
marishachu [46]

Answer:

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere =  +3.0 μC =3\times 10^{-6} C

1 \mu C=10^{-6} C

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q=  -3.0 μC =-3\times 10^{-6} C

Number of electrons = n

Charge on a single electron, e = -1.602\times 10^{-19} C

Q = n × e

-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)

n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

4 0
3 years ago
A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and
IrinaK [193]

Answer:

34.02 g.

Explanation:

Hello!

In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol

So probably, the gas may be H₂S.

Best regards!

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Answer:

I think it would be the last answer

Explanation:

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