Answer:
607 ppm
Explanation:
In this case we can start with the <u>ppm formula</u>:
If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of 
, because the molarity formula is:
In other words:
If we use the <u>atomic mass</u> of 
(19 g/mol) we can convert from mol to g:
Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:
Finally we can <u>divide by 1 L</u> to find the ppm:
<u>We will have a concentration of 607 ppm.</u>
I hope it helps!
To determine the total charge of the protons in the gas, we need to know the number of protons that are present. We use Avogadro's number to know such value. We do as follows:
2.2 mol ( 6.022x10^23 protons / 1 mol ) = 1.325x10^24 protons
Total charge = 1.6021766208×10^−19 C (1.325x10^24) = 212262.77 C
No. It appears behind the equation
Answer:
The chemical term in the equation for the precipitate of AgCl(s) is n=3.54*10^-3
Explanation:
the quantity of AgCl(s) in moles is:
n = 0.508g / 143.32 g/mol = 3.54*10^-3 mol
to verify it the mass of AgNO3 involved in the reaction should be
n AgNO3 required = n = 3.54*10^-3 mol
the mass of n involved should be higher than n AgNO3
n existing = V*N = 0.523 mol/L * 35*10^-3 L = 18.305*10^-3 mol
It’s mass because the law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed.
