Answer:
1
the equation (x-4)^2-17=8 has two solutions because <u>it is in a quadratic form.</u>
(x-4)^2-17=8
x²-8x+16-17-8=0
x²-8x-9=0
Doing middle term factorization
x²-9x+x-9=0
x(x-9)+1(x-9)=0
(x-9)(x+1)=0
either
<u>x=9</u>
<u>x=9or</u>
<u>x=9orx=-1</u>
2.
x^2+4x+3=0:
Doing middle term factorization
x²+3x+x+3=0
x(x+3)+1(x+3)=0
(x+3)(x+1)=0
either
x=-3
or
x=-1
<u>Josh’s solution is incorrect because he missed x=-3.</u>
<u>3</u><u>.</u>
x^2-6x+7=0
By <u>using</u><u> </u><u>quadratic</u><u> </u><u>equation</u><u> </u><u>f</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u><u>:</u>
Comparing above equation with ax²+bx+c=0
we get
a=1
b=-6
c=7
Now
we have
x=
x=
x=
x=
Taking positive
<u>x</u>=
taking negative
<u>x</u>=
The equestion is
2x^2-5x-12=0
we can either try to factor, or use quadratic formula
trial and errot
(x-4)(2x+3)=0
set to zero
x-4=0
x=4
2x+3=0
2x=-3
x=-3/2
x=-3/2 or 4
Answer:
3/2
Step-by-step explanation:
to divide fractions you just have to multiply them by the reciprocal.
so, instead of 3/4 divided by 1/2
it's changed to 3/4 * 2/1
then you just multiply the numerators together and the denominators together
3*2/4*1
6/4
3/2
3/2
Goodluck with your schoolwork/homework.
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apologies in advance for any errors or bad explanations.
Answer:
5 = 6q - 30 - 19
5 = 6q - 49
54 = 6q
9 = q
Step-by-step explanation:
Answer:
Taking the square root
Step-by-step explanation:
Alternatively, you can use a difference of squares to factor and solve:
