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kirill [66]
2 years ago
8

HELPPP!!! WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
masha68 [24]2 years ago
3 0

Answer:

Step-by-step explanation:

15000*.925^t

to decrease something by 7.5% you mulitply it by (1-.075)= .925

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C: 288 feet
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Bt= 8500 *(8/27)^t/3After a special medicine is introduced into a Petri dish full of bacteria, the number of bacteria remaining
ozzi

Answer:

Every 1.71 seconds, the bacteria loses \frac{1}{2}

Step-by-step explanation:

Given

B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\

Required [Missing from the question]

Every __ seconds, the bacteria loses \frac{1}{2}

First, we model the function from t/3 to t.

B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\

Apply law of indices

B(t) = 8500 * (\frac{8^\frac{1}{3}}{27^\frac{1}{3}})^t

Evaluate each exponent

B(t) = 8500 * (\frac{2}{3})^t --- This gives the number of bacteria at time t

At time 0, we have:

B(0) = 8500 * (\frac{2}{3})^0

B(0) = 8500 * 1

B(0) = 8500

Let r be the time 1/2 disappears.

When 1/2 disappears, we have:

B(r) = \frac{B(0)}{2}

B(r) = \frac{8500}{2}

B(r) = 4250

So, we have:

B(t) = 8500 * (\frac{2}{3})^t

Substitute r for t

B(r) = 8500 * (\frac{2}{3})^r

Substitute B(r) = 4250

4250 = 8500 * (\frac{2}{3})^r

Divide both sides by 8500

\frac{4250}{8500} =  (\frac{2}{3})^r

\frac{1}{2} =  (\frac{2}{3})^r

Take log of both sides

log(\frac{1}{2}) = log (\frac{2}{3})^r

Apply law of logarithm

log(\frac{1}{2}) = r\ log (\frac{2}{3})

Make r the subject

r = log(\frac{1}{2}) / log (\frac{2}{3})

r = \frac{-0.3010}{-0.1761}

r = 1.71

<em>Hence, it reduces by 1/2 after every 1.71 seconds</em>

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Answer:

Step-by-step explanation:

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