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2 years ago

What is the 6th multiple of 13?? I have no idea and I’m in set 1 rip

Mathematics

2 answers:

ki77a [65]2 years ago

8 0

Answer:

Step-by-step explanation:

Write out the 13 times tables: 13, 26, 39, 52, 65, 78, ... 78 is the 6th number.

You can also do 13 × 6 which is 78.

Hope this helps!

lyudmila [28]2 years ago

7 0

Answer:

Step-by-step explanation:

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If a= -3 and b = -8 , find the value of 2a^2 +5|b|

balu736 [363]

The answer is 76. 2(-3)=-6 -6(-6)=36. 5 times the absolute value of 8 is 40. 36+40=76

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3 years ago

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

3 years ago

I'll. ark brainlyest and give a lot of points for answering this right

valina [46]

Answer:

$\displaystyle T'( 2,4)$

$\displaystyle U'( 1,1)$

$\displaystyle S' ( 3,2)$

Step-by-step explanation:

we current vertices of the given triangle

$\displaystyle T( - 2,4)$
$\displaystyle U( - 1,1)$
$\displaystyle S ( - 3,2)$

remember that,

$\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \: over \: y - axis}( - x,y)$

so we obtain:

$\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \: over \: y - axis}T'( 2,4)$

$\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \: over \: y - axis}U' ( 1,1)$

$\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \: over \: y - axis}S'( 3,2)$

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3 years ago

Andre is running in an 80-meter hurdle race. There are 8 equally-space hurdles on the race track. The first hurdle is 12 meters

evablogger [386]

Answer:

600 and 3

Step-by-step explanation:

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3 years ago

PLS HELP ME WITH GEOMETRY PLSAND THANK YOU

Alecsey [184]

Answer:

Yes

Step-by-step explanation:

They are equal acute triangles, are congurent. Your welcom

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2 years ago