Question

I'll. ark brainlyest and give a lot of points for answering this right ​

Answer 1

Answer:

$\displaystyle T'( 2,4)$

$\displaystyle U'( 1,1)$

$\displaystyle S' ( 3,2)$

Step-by-step explanation:

we current vertices of the given triangle

• $\displaystyle T( - 2,4)$
• $\displaystyle U( - 1,1)$
• $\displaystyle S ( - 3,2)$

remember that,

$\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \: over \: y - axis}( - x,y)$

so we obtain:

$\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \: over \: y - axis}T'( 2,4)$

$\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \: over \: y - axis}U' ( 1,1)$

$\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \: over \: y - axis}S'( 3,2)$