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frutty [35]
2 years ago
9

Find the value of x (x+5)+(5-x)+(x+2)=10

Mathematics
2 answers:
Doss [256]2 years ago
7 0

Answer:

x = -2

Step-by-step explanation:

1) Rewrite the equation to remove unnecessary parenthesis: x + 5 + 5 - x + x + 2 = 10

2) Remove the opposite variables: 5 + 5 + x + 2 = 10

3) Calculate the sum of the numbers on the lefthand side: 12 + x = 10

4) Subtract 12 from both sides so that x is by itself: x = 10 - 12

5) Solve the equation on the right, and you get your answer: x = -2

lukranit [14]2 years ago
3 0

Step-by-step explanation:

<u>★</u><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>T</u><u>e</u><u>r</u><u>m</u><u>,</u>

{ \sf{ \green{ { \underline{ (x+5)+(5-x)+(x+2)=10}}}}}

<u>★</u><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>

<u>☼︎</u><u>A</u><u>r</u><u>r</u><u>a</u><u>n</u><u>g</u><u>e</u><u> </u><u>T</u><u>e</u><u>r</u><u>m</u><u>s</u>

...{ \sf{ \longmapsto{(x+5)+(5−x)+(x + 2)=10}}}

...{ \sf{ \longmapsto{(x+5)+(−x+5)+(x+2)=10}}}

<u>☼︎</u><u>H</u><u>e</u><u>r</u><u>e</u><u> </u><u>W</u><u>e</u><u> </u><u>W</u><u>i</u><u>l</u><u>l</u><u> </u><u>Eliminate redundant</u>

<u>...{ \sf{ \longmapsto{x+5)x+5+x+2=10}}}</u>

<u>☼︎</u><u>A</u><u>d</u><u>d</u>

<u>...{ \sf{ \longmapsto{x+12−x+x=10}}}</u>

<u>☼︎</u><u>Combine</u>

<u>...{ \sf{ \longmapsto{1x+12=10}}}</u>

<u>☼︎</u><u>M</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>y</u><u> </u><u>B</u><u>y</u><u> </u><u>1</u>

{ \sf {\longmapsto \: {x + 12=10}}}

<u>☼︎</u><u>Subtract </u><u> </u><u>12</u><u> from both sides</u>

<u>{ \sf {\longmapsto \: {x+12−12=10−12}}}</u>

<u>☼︎</u><u>S</u><u>o</u><u> </u><u>A</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>S</u><u>i</u><u>m</u><u>p</u><u>l</u><u>i</u><u>f</u><u>i</u><u>n</u><u>g</u><u> </u><u>I</u><u>t</u><u> </u><u>W</u><u>e</u><u> </u><u>G</u><u>e</u><u>t</u><u>,</u>

{ \underline {\bf {\longmapsto {\boxed{ \sf {\green{x =  - 2}}}}}}}

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