All categories

2 years ago

Anyone know how to do this?¿?¿

Mathematics

2 answers:

vichka [17]2 years ago

7 0

0.65 x 40 = 26
So the answer is 26 pounds.

DanielleElmas [232]2 years ago

4 0

Change 65% to a decimal: 0.65
Since "of" in math means times, 0.65 x 40 = 26

You might be interested in

Find g in the triangle

34kurt

Answer:

Step-by-step explanation:

57 + 94= 151

so 180 - 151 = 29

hope this helps

8 0

2 years ago

Write the word namefor the decimal 31.903

Alecsey [184]

Thirty-one and 903 thousandths

5 0

1 year ago

Find the average of the following set of numbers 11,14,25,-7,-9

lord [1]

11+14+25+-7+-9=34 34/5= 6.8

6.8 is the average

8 0

2 years ago

If Alex and Brandon work together, they will finish cleaning the school in 15 hours. Working alone, Brandon can finish the same

andriy [413]

Answer:

Alex can do the job in 60 days alone.

Step-by-step explanation:

Alex and Brandon working together, they can finish the job of cleaning the school in 15 hours. Brandon alone in 20 hours can finish the job.

So, Brandon can complete $\frac{1}{20}$ part of the job in one hour.

Let, Alex alone can finish the same job in x hours.

So, Alex can complete $\frac{1}{x}$ part of the job in one hour.

So, working together they do $(\frac{1}{20} + \frac{1}{x}) = \frac{x + 20}{20x}$ part of the whole job in one hour.

Hence, from the conditions given we can write

$\frac{x + 20}{20x} = \frac{1}{15}$

⇒ 15x + 300 = 20x

⇒ 5x = 300

⇒ x = 60 days.

Therefore, Alex can do the job in 60 days alone. (Answer)

3 0

2 years ago

Need help on probability. Please explain how you did it so I can know how to do it.

Galina-37 [17]

Answer:

$\text{P}(B \text{ or }C)=\dfrac{5}{6}$

Step-by-step explanation:

Mutually Exclusive Events

For two events, A and B, where A and B are mutually exclusive:

$\boxed{\text{P}(A \text{ or }B)=\text{P}(A)+\text{P}(B)}$

Probability distribution table:

$\begin{array}{|c|c|c|c|c|c|c|c|}\cline{1-7} x & 1 & 2 & 3 & 4 & 5 & 6 \\\cline{1-7} \text{P}(X=x)\phantom{\dfrac11}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}\\\cline{1-7}\end{array}$

where X is the score on a fair, six-sided dice.

P(B or C) means "the probability of rolling an even number or a multiple of 3".

As an even number of a fair, six-sided dice can never be a multiple of 3, the two events B and C are mutually exclusive.

Calculate the probabilities for events B and C.

Event B

Rolling an even number.

$\begin{aligned}\implies \text{P}(X \text{ is even})&=\text{P}(2 \text{ or }4\text{ or }6)\\\\&=\text{P}(X=2)+\text{P}(X=4)+\text{P}(X=6)\\\\& = \dfrac{1}{6}+ \dfrac{1}{6}+ \dfrac{1}{6}\\\\&=\dfrac{3}{6}\end{aligned}$

Event C

Rolling a multiple of 3.

$\begin{aligned}\implies \text{P}(X \text{ is multiple of 3})&=\text{P}(3 \text{ or }6)\\\\&=\text{P}(X=3)+\text{P}(X=6)\\\\& = \dfrac{1}{6}+ \dfrac{1}{6}\\\\&=\dfrac{2}{6}\end{aligned}$

Solution

$\begin{aligned}\implies \text{P}(B \text{ or }C)&=\text{P}(B)+\text{P}(C)\\\\& = \dfrac{3}{6}+\dfrac{2}{6}\\\\& = \dfrac{5}{6}\end{aligned}$

6 0

1 year ago

Read 2 more answers