Sqare √113
113
10^2=100, so √100=10
11^2=121 so √121=11
√100<√113<√121
so therfor
10<√113<11
it is between 10 and 11
24
i'm pretty sure of this, if those are the four possible answers.
<h3>I'll teach you how solve X/3=-19</h3>
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X/3=-19
Multiply both sides by 3:
3x/3= 3(-19)
Simplify:
x= -57
Your Answer Is x= -57
plz mark me as brainliest :)
