Question

What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capacity of the pellet is 56 J/degrees celsius. the pellet is initially at 113 degrees celsius.

Answer 1

42.34 g of water could be warmed from 21.4°C to 43.4°C  by the pellet dropped inside it

Heat loss by the pellet is equal to the Heat gained by the water.

$q_{w} = -q_{p}$ ….(1)

where, $q_{w}$ is the heat gained by water

$q_{p}$ is the heat loss by pellet

$q_{w}$ = mCΔT

where m = mass of water

C = specific heat capacity of water = 4.184 J/g-°C

ΔT = Increase in temperature

ΔT for water = 43.4 - 21.4 = 22°C

$q_{w}$ = m × 4.184 × 22 …. (2)

Now

$q_{p}$ = $H_{c}$ ×ΔT

where $H_{c}$ = Heat capacity of pellet = 56J/°C

Δ T for pellet = 43.4 - 113 =- 69.6°C

$q_{p}$ = 56 × -69.6 = -3897.6 J

From equation (1) and (2)

-m× 4.184 × 22 =-3897.6

m= 42.34 g

Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.

Learn more about specific heat here brainly.com/question/16559442

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