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2 years ago

CaCO2=CaO + CO₂ How do I balance this equation?

Chemistry

2 answers:

otez555 [7]2 years ago

5 0

2CaCO2–>2CaO+CO2
2 Calciums on both sides, 2 Carbons on both sides, and 4 Oxygens on both sides.

7nadin3 [17]2 years ago

4 0

Answer:

2CaO + 2CO2 → 2CaCO2 + O2 is right

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What is the other product for this reaction? Hbr + NaOH —> ( select 2)

ratelena [41]

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Answer: HBr + NaOH = nabr + h2o

Explanation:

I hope this helped!

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3 years ago

Have heat waves ever affected the world in a way? Explain.

lubasha [3.4K]

Answer: Yes, they have.

Explanation: The frequency, severity, and length of heat waves are increasing. Heat and humidity already kill an average of 1,300 people in the U.S. each year. Deadly heat waves of at least 20 days affect 30% of the earth's population. That will increase to 75% by 2100 if global warming isn't stopped.

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3 years ago

A pogo stick bounces 30 M in 10 secs what is the bouncers average speed?

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I would love to help but it is 3 or is it 3 million?

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4 years ago

Read 2 more answers

How do we determine how many orbitals to draw?

Anna [14]

Answer:

Explanation:

Image result for How do we determine how many orbitals to draw?

An s orbital is a sphere. In two dimensions, we draw it as a circle.

...

One orbital looks like a p orbital with two doughnuts around its middle.

Two orbitals have eight lobes pointing towards the corners of a cube.

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4 years ago

4.2 g of 1,4-di-t-butyl-2,5-dimethoxybenzene (250.37 g/mol) were synthesized by reacting 10.4 mL of t-butyl alcohol (MW 74.12 g/

nalin [4]

Answer:

Percentage yield of 1,4-di-t-butyl-2,5-dimethoxybenzene is 41.40%.

Explanation:

Here, in the reaction sulfuric acid is playing the role of catalyst by donating its proton in initial stage of the reaction and in the end of the reaction the proton is returned back to sulfuric acid.

Mass = Density × Volume

Mass of t-butyl alcohol = $0.79 g/mL\times 10.4 mL=8.219 g$

Moles of t-butyl alcohol = $\frac{8.219 g}{74.12 g/mol}=0.11084 mol$

Moles of 1,4-dimethoxybenzene = $\frac{5.6 g}{138.17 g/mol}=0.04052 mol$

According to reaction 2 mol of t-butyl alcohol reacts with 1 mol of 1,4-dimethoxybenzene.

Then 0.11084 moles of t-butyl alcohol will react with :

$\frac{1}{2}\times 0.11084 mole=0.05542 mol$ of 1,4-dimethoxybenzene.

This means that moles of 1,4-dimethoxybenzene are limited and moles of t-butyl alcohol are in excess.So, the moles of product will depend upon the moles of 1,4-dimethoxybenzene.

According top reaction 1 mol of 1,4-dimethoxybenzene gives 1 mol of 1,4-di-t-butyl-2,5-dimethoxybenzene.

Then 0.04052 moles of 1,4-di-t-butyl-2,5-dimethoxybenzene will give:

$\frac{1}{1}\times 0.04052 mol= 0.04052 mol$ of 1,4-di-t-butyl-2,5-dimethoxybenzene.