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3 years ago

What’s the similarity between nuclear fission and nuclear fusion

Physics

1 answer:

Darya [45]3 years ago

4 0

Explanation:

At first sight, it doesn’t make sense that both fission and fusion release energy.

The key is in how tightly the nucleons are held together in a nucleus. If a nuclear reaction produces nuclei that are more tightly bound than the originals, then the excess energy will be released.

It turns out that the most tightly bound atomic nuclei are around the size of iron-56.

Thus, if you split a nucleus that is much larger than iron into smaller fragments, you will release energy because the smaller fragments are at a lower energy than the original nucleus.

If instead you fuse very light nuclei to get bigger products, energy is again released because the nucleons in the products are more tightly bound than in the original nuclei.

https://socratic.org/questions/how-are-fusion-and-fission-similar

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The protons in a nucleus are approximately 2 ✕ 10^−15 m apart. Consider the case where the protons are a distance d = 1.93 ✕ 10^

Bond [772]

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3 years ago

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Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The

sergij07 [2.7K]

The two flaws in her experiment’s design are

<span>- She introduced at least one confounding variable.</span> <span>- She tried to test multiple hypotheses at a time</span>

In the above mentioned experiment she had to have four samples to prove four hypotheses, each one separately and not to mix two hypotheses in an alone sample, that what it brings as consequence is the confusion.

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3 years ago

A positive point charge (q = +8.65 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 2.97 m. A p

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Answer:

$r_B = 1.88 m$

Explanation:

As we know that work done by electric force is given as

$W_e = -q\Delta V$

so here we know that charge is moving from

$r_A = 2.97 m$

to another position

so we will have

$W_{AB} = \frac{kq_1q_2}{r_A} - \frac{kq_1q_2}{r_B}$

$-6.95\times 10^{-9} = (9\times 10^9)(8.65\times 10^{-8})(4.56\times 10^{-11})(\frac{1}{2.97} - \frac{1}{r_B})$

$-0.196 = (\frac{1}{2.97} - \frac{1}{r_B})$

$r_B = 1.88 m$

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4 years ago

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2 years ago

Due to radiation and absorption, what is the maximum flame temperature in a fire?

ludmilkaskok [199]

The maximum flame temperature in a fire is 1500-1600K due to radiation and absorption.

<h3>What do you mean by radiation and absorption?</h3>

In physics, matter (usually electrons bound in atoms) absorbs electromagnetic radiation in order to convert the energy of a photon into the internal energy of the absorber (for example, thermal energy). Attenuation, or the steady decrease in light wave intensity as it travels through a medium, is a prominent effect. In some circumstances (optics), the medium's transparency changes by a factor that varies as a function of wave intensity, leading to saturable absorption (or nonlinear absorption), even though the absorption of waves typically does not depend on their intensity (linear absorption).

To learn more about absorption, Visit:

brainly.com/question/26061959

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1 year ago