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seraphim [82]
3 years ago
5

There are 5000 books in the​ town's library. Of​ these, 4,000 are fiction. To find the percent of the books that are​ fiction, f

irst set up the percent equation. Then find the percent.
Mathematics
2 answers:
deff fn [24]3 years ago
8 0

Answer:

80%

Step-by-step explanation:

4000 / 5000 * 100 = 80%

katrin2010 [14]3 years ago
7 0

Answer:

0.8%

Step-by-step explanation:

%= \frac{4000}{5000} = 0.8 = .8%

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Drupady [299]

Answer: The answer is Yes. A square is a rectangle because it possesses all the properties of a rectangle. These properties are: Interior angles measure 90∘ each.

Explanation:

Definition of a Rectangle:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, opposite sides are parallel and of equal length.

Definition of a Square:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, all sides have equal length

As you can see the first part of the definition of a square and rectangle are the same.

However, a square is a special case of a rectangle.

When all 4 sides of a rectangle are equal then the rectangle is a square.

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Step-by-step explanation:

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3 years ago
Which line is parallel to y=-4x+3?
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Step-by-step explanation:

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3 years ago
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3 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
4 years ago
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