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Montano1993 [528]
3 years ago
15

PLEASE HELP GIVING BRAINLIEST !!!!

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

hi :):):):):):):):) don't ignore me T_T

Step-by-step explanation:

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What is the standard form of the number shown in this calculator display?
kicyunya [14]

Answer:

5.93 × 10-5

Step-by-step explanation:

4 0
1 year ago
With an ambiguous plot, no one could understand the film's premise.
rodikova [14]

Answer:

Her songs are intentionally ambiguous.

Explanation:

In visual art, certain images are visually ambiguous, such as the Necker cube, which can be interpreted in two ways. Perceptions of such objects remain stable for a time, then may flip, a phenomenon called multistable perception. The opposite of such ambiguous images are impossible objects.

7 0
3 years ago
The variable z is directly proportional to x. When x is 6, z has the value 60. What is the value of z when x = 11?
user100 [1]

Answer:

  110

Step-by-step explanation:

z is apparently 10 times x.

10 times 11 is 110.

6 0
3 years ago
How does x/2-12=-14 I don’t understand where the negative comes from
goblinko [34]
Solve x by simplifying both sides of the equation & then isolating the variable x=-4 & the negative comes in from the -12
4 0
3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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