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3 years ago

PLEASE HELP GIVING BRAINLIEST !!!!

Mathematics

1 answer:

Contact [7]3 years ago

6 0

Answer:

hi :):):):):):):):) don't ignore me T_T

Step-by-step explanation:

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The Barkers started their trip with a full tank of gas and a total of 39,872 miles on their car. They stopped 4 hours later and

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Answer:

27.5 miles per gallon

Step-by-step explanation:

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2 years ago

What is the distance between p(-300, 200) and Q(500, 400)?

alina1380 [7]

Answer:

200 √17

Step-by-step explanation:

distance between two points (x,y) and (x',y')

D² = (x' - x)² + (y' - y)²

D² = (500 - (-300))² + (400 - 200)² = 640000 + 40000 = 680000

D = √680000 = √4 x 17 x 10000 = 200 √17

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3 years ago

5x+6=61 Show Step By Step

Annette [7]

5x =61-6
5x= 55
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3 years ago

Read 2 more answers

Katie bought 4 sweaters that each cost the same amount and 1 skirt that cost $20. the items she bought cost a total of 160$. wri

Rufina [12.5K]

Answer:

160-20=140. 140/4=$35.

4 0

3 years ago

Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of

prohojiy [21]

Answer:

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

Step-by-step explanation:

Information given

$\bar X¿ 17.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s¿4.2 represent the sample standard deviation

n¿65 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=65-1=64$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value would be $t_{\alpha/2}=1.669$

And replacing we got

$17.5-1.669\frac{4.2}{\sqrt{65}}=16.63$

$17.5+1.669\frac{4.2}{\sqrt{65}}=18.37$

For the 95% confidence the critical value is $t_{\alpha/2}=1.998$

$17.5-1.998\frac{4.2}{\sqrt{65}}=16.46$

$17.5+1.998\frac{4.2}{\sqrt{65}}=18.54$

8 0

3 years ago