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Montano1993 [528]
3 years ago
15

PLEASE HELP GIVING BRAINLIEST !!!!

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

hi :):):):):):):):) don't ignore me T_T

Step-by-step explanation:

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Eric got $70 for his birthday. He plans to use some of this money to buy a new video game, but he wants to have at least $14 rem
sdas [7]

Answer:

g ≤ 56

Step-by-step explanation:

56 + 14 ≤ 70

70 ≤ 70

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3 years ago
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What is the ratio of 12​
evablogger [386]

12 to 1

is the ratio :)

8 0
3 years ago
Given: p: 7x+1=8 q: 3x+4=7 p->q write the inverse in if-then form
Lady_Fox [76]
X= 1 .........................

3 0
3 years ago
50 POINTS EACH
Andrews [41]

Since s and t are complimentary, that means ∠s + ∠t = 90

From the picture, we also know that ∠t + ∠LGM = 90

Set them equal to each other:

∠s + ∠t = ∠t + ∠LGM, solve:

∠s = ∠LGM

Now using the fact that tangent = opposite/adjacent:

tan (∠s) = \frac{y}{h}

tan (∠s) = \frac{h}{x}

Set them equal to each other to get:

\frac{y}{h} = \frac{h}{x}

Solve:

h^{2}= xy\\h = \sqrt{xy}

Part B:

Using tan (∠s) = \frac{y}{h}

We get: h = \frac{3}{tan38} = 3.84 meters

Hope that helps!

3 0
3 years ago
Find a and b such that gcd(a, b) = 14, a > 2000, b > 2000, and the only prime divisors of a and b are 2 and 7.
choli [55]

Answer:

a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

a = 2^\alpha.14 \\b = 7^\delta.14

All we have left to do is find the possible values for \alpha and \delta so that a>2000 \ , b>2000 and that only happens if \alpha\geq 8 and \delta\geq 3

8 0
3 years ago
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