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Montano1993 [528]
3 years ago
15

PLEASE HELP GIVING BRAINLIEST !!!!

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

hi :):):):):):):):) don't ignore me T_T

Step-by-step explanation:

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Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and the critical value would be t_{\alpha/2}=1.669

And replacing we got

17.5-1.669\frac{4.2}{\sqrt{65}}=16.63    

17.5+1.669\frac{4.2}{\sqrt{65}}=18.37    

For the 95% confidence the critical value is t_{\alpha/2}=1.998

17.5-1.998\frac{4.2}{\sqrt{65}}=16.46    

17.5+1.998\frac{4.2}{\sqrt{65}}=18.54    

Step-by-step explanation:

Information given

\bar X¿ 17.5 represent the sample mean

\mu population mean (variable of interest)

s¿4.2 represent the sample standard deviation

n¿65 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=65-1=64

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and the critical value would be t_{\alpha/2}=1.669

And replacing we got

17.5-1.669\frac{4.2}{\sqrt{65}}=16.63    

17.5+1.669\frac{4.2}{\sqrt{65}}=18.37    

For the 95% confidence the critical value is t_{\alpha/2}=1.998

17.5-1.998\frac{4.2}{\sqrt{65}}=16.46    

17.5+1.998\frac{4.2}{\sqrt{65}}=18.54    

8 0
3 years ago
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