Answer:
b
Step-by-step explanation:
Answer:
6/7 ≈ 85.7%
Step-by-step explanation:
The probability that a 0 was transmitted and received is 0.5·0.9 = 0.45.
The probability that a 1 was transmitted and a 0 received is 0.5·0.15 = 0.075.
Then the probability that a 0 was received is 0.45 +0.075 = 0.525.
The probability of interest is ...
p(0 transmitted | 0 received) = p(0 transmitted & received)/p(0 received)
= 0.45/0.525 = 6/7 ≈ 85.7%
Answer:
See Explanation
Step-by-step explanation:
<em>The question is incomplete, as the required data to answer the question are missing.</em>
<em>However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.</em>
<em>Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data</em>
<em>Then, make comparison</em>
<em />
To do this, I will use the following assumed datasets.
IQR is calculated as:
is of the upper half
is of the lower half
For Joe, we have:
The median is then calculated as:
For, the lower half:
So:
For the upper half:
So:
When the same process is applied to Sam's data,
Assume that:
<em>Hence, the IQR is 47 points less for Joe's data than Sam's</em>
Answer:
(0,1)
Step-by-step explanation:
Let (0,3) lies on f(x), then:
Let
To find the corresponding point that lie on g(x), we substitute x=0
This implies that:
But f(0)=3
We substitute to get:
The required point is (0,1)