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tatuchka [14]
3 years ago
8

A deer named Cho was crossing the highway. Martin was driving at 60 MPH, speeding 5 MPH over the speed limit. Flem distracted Ma

rtin which caused Martin to hit the deer. What was the speed limit?:
Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

Speed limits are used in most republics to set the greatest speed at which road cars may legally journey on specific stretches of road. In the problem, the car is moving 60 mph and was speeding over 5mph above the speed limit. So therefore, 60 – 5 = 55mph is the speed limit for this road.

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Help me out with this
ArbitrLikvidat [17]

Answer:

What is 2x + 5 (y-1) when x=8 and y=5

Step-by-step explanation:

HELP ME

5 0
3 years ago
Read 2 more answers
-5(x+2y)+15(x+2y);x7and y=-7
Nat2105 [25]
I believe your answer should be 105x squared-1475x+70
sorry i'm not really sure how to put the little two above the first x but my answer is mathematically correct.
6 0
3 years ago
There are 1200 students at silver lake middle school 700 Are eighth graders what percent of the students are in the eighth grade
Leni [432]
(700/1200)*100 = 58.33%, rounding to the nearest 10th of à percent we get 60%
7 0
3 years ago
Barnabus caught 84 fish in 4 days. Each day he caught 10 more than on the day before. How many fish did he catch each of the 4 d
balandron [24]
X + x + 10 + x + 20 + x + 30 = 84.
4x + 60 = 84.
84 − 60 = 24
4x =  24.
24 / 4 = 6 = x.

Answer:
Day One:  6 fish
Day Two:  16 fish
Day Three:  26 fish
Day Four:  36 fish
5 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
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