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2 years ago

8

A deer named Cho was crossing the highway. Martin was driving at 60 MPH, speeding 5 MPH over the speed limit. Flem distracted Ma

rtin which caused Martin to hit the deer. What was the speed limit?:

1 answer:

bagirrra123 [75]2 years ago

8 0

Speed limits are used in most republics to set the greatest speed at which road cars may legally journey on specific stretches of road. In the problem, the car is moving 60 mph and was speeding over 5mph above the speed limit. So therefore, 60 – 5 = 55mph is the speed limit for this road.

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Help its ugent ill mark brainleyest

Brilliant_brown [7]

Answer:

more than one triangle

Step-by-step explanation:

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2 years ago

Math problem help me

Ratling [72]

Answer:

$y=3x+2$

Step-by-step explanation:

To find the equation, use the slope-intercept formula:

$y=mx+b$

m is the slope and b is the y-intercept. Now, it'll really help to draw a line through the points, connecting them. If you look at point (0,2), we can see that this is the y-intercept (where a point sits on the y-axis when x=0). You can insert this into the equation by taking the y value:

$(0,2)\\y=mx+2$

Now, take any two points to find the slope. To make it easier, I'll use (1,5) and (0,2). Use the slope formula for when you know two points:

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$(1(x1),5(y1))\\(0(x2),2(y2))\\\\\frac{2-5}{0-1}$

Solve:

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6 0

2 years ago

10. Rotate the figure shown 180° clockwise. Record the coordinates of the 3 points<br> image.

inna [77]

Answer:

$J' = (6,7)$

$K' = (6,2)$

$L'=(3,7)$

Step-by-step explanation:

From the attachment, we have:

$J = (-6,-7)$

$K = (-6,-2)$

$L = (-3,-7)$

Rotation: 180 degrees clockwise

Required

Find J', K' and L'

When a point (x, y)is rotated 180 degree clockwise, the resulting point is: (-x, -y)

So, we have:

$J' = (6,7)$

$K' = (6,2)$

$L'=(3,7)$

3 0

2 years ago

Mary has 96 muffins which she needs to box up, 5 of which are blueberry, into dozens. How many boxes dose he need

lesya692 [45]

Answer:

8

Step-by-step explanation:

Mary needs 8 boxes to put 96 muffins in dozens so 96÷12 gives you 8

8 0

2 years ago

Read 2 more answers

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

2 years ago