<h2>
Hello!</h2>
The answer is:
The range of the function is:
Range: y>2
or
Range: (2,∞+)
<h2>
Why?</h2>
To calculate the range of the following function (exponential function) we need to perform the following steps:
First: Find the value of "x"
So, finding "x" we have:
Second: Interpret the restriction of the function:
Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.
So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.
Hence, the range of the function is:
Range: y>2
or
Range: (2,∞+)
Note: I have attached a picture (the graph of the function) for better understanding.
Have a nice day!
<h3>
Answer: 4</h3>
================================================
Explanation:
We'll only focus on points J and K.
J = (3, -6)
K = (-1, -6)
Because these two points have the same y coordinate (which is -6), this means we can ignore those values and subtract the x coordinates
3 minus (-1) = 3 - (-1) = 3 + 1 = 4
Or we could plot points J and K on the same xy grid system, and count out the number of spaces between J and K. You should count out 4 spaces.
This means segment JK is 4 units long.
Answer:
Step-by-step explanation:
we know that
The <u><em>Two-Tangent Theore</em></u>m states that if two tangent segments are drawn to one circle from the same external point, then they are congruent
so
Applying the Two-Tangent Theorem at each vertex of the triangle
The perimeter of the triangle is equal to
we'd do the same as before on this one as well.
if we take 27.99 to be the 100%, what is 12 off of it in percentage?
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.
For more context let's look at the first equation in the problem that we can apply this to:
Through zero property we know that the factor
can be equal to zero as well as
. This is because, even if only one of them is zero, the product will immediately be zero.
The zero product property is best applied to
factorable quadratic equations in this case.
Another factorable equation would be
since we can factor out
and end up with
. Now we'll end up with two factors,
and
, which we can apply the zero product property to.
The rest of the options are not factorable thus the zero product property won't apply to them.
