Let X = number of minutes.
Plan A = 50 + 0.04X
Plan B = 60 + 0.02X
50 + 0.04X = 60 + 0.02X
Subtract 50 from each side:
0.04X = 10 + 0.02X
Subtract 0.02X from each side:
0.02X = 10
Divide both sides by 0.02
X = 10 / 0.02
X = 500
It will take 500 minutes.
Answer:
A is the correct answer
Step-by-step explanation:
34,272 is the answer
you have to estimate it is easy
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
6/10
300/500
30/50
60/100
12/20
