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nydimaria [60]
3 years ago
6

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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4x + 2x + 2 = 3x - 7<br> How many solutions
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Answer:

One solution (x = -3)

Step-by-step explanation:

4x + 2x + 2 = 3x - 7

6x + 2 = 3x - 7

3x = -9

x = -3

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Bezzdna [24]

a)

Dimensions: 7.5m x 4.5m

Cost , x= $14.17/m^2.

The area of the rectangular room can be calculated as,

\begin{gathered} A=7.5\times4.5 \\ =33.75m^2 \end{gathered}

Now, the cost of carpeting the rectangular room is,

\begin{gathered} C=xA \\ =14.17\times33.75 \\ =478.24\text{ } \end{gathered}

Therefore, the cost of carpeting the room with dimensions 7.5m x 4.5m is $478.24.

b)

Dimensions: 17 yd. x 12 yd.

Cost, x= $25/yd^2.

The area of the rectangular room can be calculated as,

\begin{gathered} A=17\times12 \\ =204yd^2 \end{gathered}

Now, the cost of carpeting the rectangular room is,

\begin{gathered} C=xA \\ =25\times204 \\ =5100 \end{gathered}

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Fofino [41]

Answer:

a. $17.50

b. $11.25

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First, set up an equation:

20 - 1.25x = m

Now let's substitute in for x (which is how many snacks you buy) to solve for m (the amount of money you have left):

20 - 1.25 ( 2 ) = m

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20 - 1.25 ( 12 ) = m

20 - 15 = m

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