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nydimaria [60]
3 years ago
6

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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The explicit formula for the geometric sequence c_{n} is

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Step-by-step explanation:

The formula of the nth term of a geometric sequence is

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The geometric sequence of c_{n} is 6 , -2 , \frac{2}{3} , \frac{-2}{9} , \frac{2}{27}

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∴ r=\frac{-1}{3}

∵ c_{n}=c_{1}(r)^{n-1}

- Substitute the value of c_{1} and r in the rule above

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The explicit formula for the geometric sequence c_{n} is

c_{n}=6(\frac{-1}{3})^{n-1}

Learn more:

You can learn more about the geometric sequence in brainly.com/question/1522572

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