Mass of calcium carbonate (in grams) can be dissolved by 4.1 g of Hcl is 5.62g.
<h3>What is balanced equation?</h3>
A balanced equation is one for a chemical reaction in which the overall charge and the number of atoms for each component are the same for both the reactants and the products. In other words, the mass and charge of both sides of the reaction are equal.
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,
CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂
Hydrochloric acid has a molecular weight of 36.45 g/mol compared to calcium carbonate's molecular weight of 100 g/mol. According to the equation above, 72.9 g of hydrochloric acid may dissolve 100 g of calcium carbonate.
x = (4.1 g HCl)(100 g CaCO3 / 72.9 HCl)
x = 5.62 g.
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Answer:
Your strategy here will be to use the molar mass of potassium bromide,
KBr
, as a conversion factor to help you find the mass of three moles of this compound.
So, a compound's molar mass essentially tells you the mass of one mole of said compound. Now, let's assume that you only have a periodic table to work with here.
Potassium bromide is an ionic compound that is made up of potassium cations,
K
+
, and bromide anions,
Br
−
. Essentially, one formula unit of potassium bromide contains a potassium atom and a bromine atom.
Use the periodic table to find the molar masses of these two elements. You will find
For K:
M
M
=
39.0963 g mol
−
1
For Br:
M
M
=
79.904 g mol
−
1
To get the molar mass of one formula unit of potassium bromide, add the molar masses of the two elements
M
M KBr
=
39.0963 g mol
−
1
+
79.904 g mol
−
1
≈
119 g mol
−
So, if one mole of potassium bromide has a mas of
119 g
m it follows that three moles will have a mass of
3
moles KBr
⋅
molar mass of KBr
119 g
1
mole KBr
=
357 g
You should round this off to one sig fig, since that is how many sig figs you have for the number of moles of potassium bromide, but I'll leave it rounded to two sig figs
mass of 3 moles of KBr
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
360 g
a
a
∣
∣
−−−−−−−−−
Explanation:
<em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em> </em><em>3</em><em>6</em><em>0</em><em> </em><em>g</em><em> </em>
I'm not positive but I'm pretty sure its Light waves.
For this question we use Boyle's law which states the relationship between pressure and volume. At constant temperature, pressure of a gas is inversely proportional to volume of a gas.
PV = k
where P-pressure, V - volume and k - constant
Therefore P1V1 = P2V2
where parameters for 1st instance are on the left side and parameters for the 2nd instance are on the right side.
183 ml x 310 mmHg = 90.6 ml x P2
P2 = 183 x 310 / 90.6
= 626.16 mmHg
pressure required is 626.16 mmHg
Answer:
The element is Aluminium. (assuming that the given quantum number set is for the valence electron of the unknown element)
Explanation:
The given quantum numbers are:
n=3 (Principal Quantum Number)
l=1 (Azimuthal Quantum Number)
m=0 (Magnetic Quantum Number)
s= -1/2 (Spin Quantum Number)
The given set of quantum numbers refer to the 3p orbital.
Assuming that this the valence electron of the element, the unkown element is Aluminium.